Arrayfun with multiple variable?

Hi, probably this question has already received answers but what I found don't solve my problem.
I know that I have a function that requires one input i can use arrayfun like this:
A=arrayfun(@functionExample, input1);
But if I have a function that requires more than one input how can I do?
Thanks

답변 (2개)

Voss
Voss 2022년 4월 19일

0 개 추천

Two inputs:
A=arrayfun(@(x,y)functionExample(x,y), input1, input2);
Three inputs:
A=arrayfun(@(x,y,z)functionExample(x,y,z), input1, input2, input3);
And so on.

댓글 수: 3

MementoMori
MementoMori 2022년 4월 19일
Thank you.
But I have this error:
Variable number of inputs is not supported.
For more information see Tips.
MementoMori
MementoMori 2022년 4월 19일
Is this caused by varargin in the function "functionExample"
It is not required to use anonymous functions, a simple function handle works with any number of inputs:
V = arrayfun(@max,[1,2,3],[0,9,0])
V = 1×3
1 9 3

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Stephen23
Stephen23 2022년 4월 19일
편집: Stephen23 2022년 4월 19일

0 개 추천

"But if I have a function that requires more than one input how can I do?"
ARRAYFUN already works with any number of input arrays:
fnh = @(varargin)sum([varargin{:}]); % test function, any number of inputs
arrayfun(fnh,[1,2,3])
ans = 1×3
1 2 3
arrayfun(fnh,[1,2,3],[4,5,6])
ans = 1×3
5 7 9
arrayfun(fnh,[1,2,3],[4,5,6],[7,8,9])
ans = 1×3
12 15 18

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2022년 4월 19일

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2022년 4월 19일

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