Finding gradient of a part of a graph

May I know how to find the gradient of the first linear part? What function should I use?

Answer 1

[Sam Chak]

@Yen Tien Yap

Technically, if is plotted by a function f(x) with a uniform step size h, then you can use the nabla = gradient(f)/h to compute the slope of f(x).

To find the gradient of the transient response, you need to pick a point in that region, for example, , and then find the index idx that is nearest to, or exactly at this point.

You can try @Faraz Hedayati's code or this code. Both are good learning experiences for you

h = 0.01;
x = 0:h:10;
y = 1 - exp(-x/sqrt(2)).*(cos(x/sqrt(2)) + sin(x/sqrt(2)));
plot(x, y)
hold on

nabla = gradient(y)/h;
[M, idx] = max(nabla);
plot(x(idx), y(idx), 'o', 'linewidth', 1.5)

m = nabla(idx)                          % slope at point p
c = y(idx) - m*x(idx)                   % y-intercept
z = m*x + c;                            % line equation at point p
plot(x, z, 'linewidth', 1.5)
hold off

grid on
xlabel('x')
ylabel('y')
title('y = f(x) and the tangent line at the steepest slope')
legend('function f(x)', 'the point at f(p)', 'tangent line', 'location', 'best')

Result:

Note: If the spread of the data points are not uniform, then you probably need to use the interpolation technique, interp1().

https://www.mathworks.com/help/matlab/ref/interp1.html

Answer 2

[Tala]

A=your signal; dx=epsilon(2)-epsilon(1); % assuming the sampling frequency is constant

[M,I] = max(A);

B=diff(A(1:I))./dx;