Writing code to calculate difference between 2 ones in logic matrix
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Hi all, I'd like to write code to measure distance between two ones in logic matrix (1x24) attached below: I will be so grateful if someone help me. Best Regards
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/146725/image.png)
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per isakson
2015년 1월 8일
편집: per isakson
2015년 1월 8일
A starting point
num = [0,0,0,0,1,1,1,1,0,0,0,0,0,0,0,0,0,1,1,1,1,0,0,0];
bol = logical( num );
ix1 = find( bol );
dix = ix1(2:end)-ix1(1:end-1) - 1;
dix( dix >= 1 )
it returns
ans =
9
>>
 
Answer to comment, which basically is the solution by Mohammad Abouali with a few comments.
num = [0,0,0,0,1,1,1,1,0,0,0,0,0,0,0,0,0,1,1,1,1,0,0,0,0,0,0,1,1,1,0,0,0,0,0];
dn1 = diff([0,num]); % make sure the first value is zero
ix1 = find( dn1 == 1 ); % indicies of the "first ones"
dix = diff( ix1 ) -1; % distance between successive "first ones"
returns
dix =
12 9
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Mohammad Abouali
2015년 1월 8일
편집: Mohammad Abouali
2015년 1월 8일
A=[0 0 0 0 1 1 1 1 0 0 0 0 0 0 0 0 0 1 1 1 1 0 0 0 0 0 0 1 1 1 0 0 0 0 0]
diff(find(diff([0 A])>0))-1
ans =
12 9
추가 답변 (1개)
Image Analyst
2015년 1월 8일
I see you tagged it as image processing. If you want an image processing method of doing it, it would be to use regionprops to measure the "Area" (length) of the runs of zeros.
% Example 1
num = [0,0,0,0,1,1,1,1,0,0,0,0,0,0,0,0,0,1,1,1,1,0,0,0];
% Trim off leading and trailing zeros
num = num(find(num==1, 1, 'first'):find(num==1, 1, 'last'));
% Measure the lengths of the stretches/runs of zeros.
measurements = regionprops(logical(~num), 'Area');
lengthOfZeroStretches = [measurements.Area]
% Example 2
num = [0,0,0,0,1,1,1,1,0,0,0,0,0,0,0,0,0,1,1,1,1,0,0,0,0,0,0,1,1,1,0,0,0,0,0];
% Trim off leading and trailing zeros
num = num(find(num==1, 1, 'first'):find(num==1, 1, 'last'));
% Measure the lengths of the stretches/runs of zeros.
measurements = regionprops(logical(~num), 'Area');
lengthOfZeroStretches = [measurements.Area]
In the command window:
lengthOfZeroStretches =
9
lengthOfZeroStretches =
9 6
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