how can i fix it please
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Image Analyst
2022년 4월 9일
편집: Image Analyst
2022년 4월 9일
Replace "and" by a double (not single) ampersand : &&
Get rid of lines 4 and 6. MATLAB does not have a "do" and does not start and end blocks with braces.
Your while loop doesn't seem to have any way to exit if it goes into it. How could soc and Ppv change if they're variables? If they're functions, then perhaps they could come back with different values each time, but they're not. They're either scalars or arrays (which is it?).
But there's also a problem in that your while has no failsafe - no limit on the number of iterations so you could get into an infinite loop situation. More robust code would be:
maxIterations = 100000; % Way more than you think you'd ever need.
loopCounter = 0; % The failsafe
while (soc < 80) && (Ppv > 4000) && loopcounter < maxIterations
u = 0;
% Then maybe some other code that changes soc or Ppv.
% Finally increment the loop counter.
loopCounter = loopCounter + 1;
end
if loopCounter >= maxIterations
warningMessage = sprintf('Loop exited early after %d iterations', loopCounter)
uiwait(warndlg(warningMessage));
end
댓글 수: 6
khalil chnini
2022년 4월 9일
편집: khalil chnini
2022년 4월 9일
Image Analyst
2022년 4월 9일
How does soc or Ppv ever get changed inside the loop?
khalil chnini
2022년 4월 9일
Image Analyst
2022년 4월 9일
OK, then you should break out of the loop if/when the criteria gets met.
khalil chnini
2022년 4월 12일
편집: khalil chnini
2022년 4월 12일
Image Analyst
2022년 4월 12일
Somehow you are changing either soc or Ppv inside the loop. When the condition below
(soc < 80) && (Ppv > 4000) && loopcounter < maxIterations
is false, the loop will automatically exit. You said that you were getting those values inside the loop via asking the user with an input() statement, which is how I interpreted this: "w enter them as an input throu (go to ) block"
Karuppasamy Kalimuthu
2022년 4월 9일
0 개 추천
and to be replaced by &
댓글 수: 3
John D'Errico
2022년 4월 9일
Actually, no. You want to use && in an if statement. There is a difference.
Karuppasamy Kalimuthu
2022년 4월 11일
Yes. && is correct.
Walter Roberson
2022년 4월 11일
Either & or && can be used when both sides are scalars, but && would be more efficient in such a case.
If the left side is non-scalar, or the left side is scalar non-zero and the right side is non-scalar, then & must be used instead of && .
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