Solving Constrained Optimization for 4 variables (or 3?)

I am trying to solve the question from the picture below.
I dont know how to modify the original code from solving 2 variables into solving 4 variables. My friend said it was supposedly only 3 variables (x4 supposedly was x3), maybe because the typo.
There are my Matlab code

답변 (1개)

Torsten
Torsten 2022년 4월 8일
편집: Torsten 2022년 4월 8일
It's a simple linear optimization problem. If you are allowed to, use "linprog" to solve.
f = [1; 1; 1; 0];
Aeq = [3 1 0 -1;1 -2 1 0];
beq = [-5;1];
lb = [-Inf; 0 ;0 ;0];
ub = [Inf ;Inf; Inf ;Inf];
sol = linprog(f,[],[],Aeq,beq,lb,ub)

댓글 수: 7

I tried with another code from forum, but still not giving the same solution like yours
clc
clear
close all
syms l b h k lambda
A = l + b + h + 0;
V = 3*l + b - k == 0;
G = l - 2*b + h == 0;
L = A + lambda * lhs(V) + lambda * lhs(G);
dL_dl = diff(L,l) == 0;
dL_db = diff(L,b) == 0;
dL_dh = diff(L,h) == 0;
dL_dk = diff(L,k) == 0;
dL_dlambda = diff(L,lambda) == 0;
system = [dL_dl; dL_db; dL_dh; dL_dk; dL_dlambda];
[l_val, b_val, h_val, k_val, lambda_val] = solve(system, [l b h k lambda], 'Real', true)
results_numeric = double([l_val, b_val, h_val,k_val, lambda_val])
V_res = l_val + b_val + h_val + 0
V = 3*l_val + b_val - k_val;
G = l_val - 2*b_val + h_val;
Torsten
Torsten 2022년 4월 8일
편집: Torsten 2022년 4월 8일
This code is absolutely inadequate for the problem. Don't stick to it.
And I also don't see how to implement the non-negative constraints for x2 - x4 in the Lagrange approach.
Thank you for your response, perhaps I must find a book which tell me how to do with negative constraints?
Is there any reason not to use linprog ?
Tristofani Agasta
Tristofani Agasta 2022년 4월 8일
편집: Tristofani Agasta 2022년 4월 8일
Yes, because my lecturer demanding to use basic programming with steps and can be explained mathematically. Just like Gauss Elimination with some iterations without using library or toolbox
Torsten
Torsten 2022년 4월 8일
편집: Torsten 2022년 4월 8일
Then look up "simplex algorithm".
Programming it, everything is hand-made.
Thank you for your reply

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