"parameter {0} must be a real scalar" error when using parfor
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Hello,
In the following parfor loop, I want to add data into a newly created column in a mysql table by going row by row and manually inserting the data using the "update" function. But I end up getting an error, saying that the parameter isn't a scalar. I'm not sure why the error occurs since the beginning and ending values of the loop are both scalars. And if I replace "sizeOfColumn" with a literal constant, it also gives me the same error.


Thank You so much.
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Walter Roberson
2022년 4월 1일
I wonder if you need to use
data = newColumn(i,1);
?
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카테고리
도움말 센터 및 File Exchange에서 Parallel for-Loops (parfor)에 대해 자세히 알아보기
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