How to use sprintf in a variable name?

For example, I want to do this (but it gives an error):
row = 4
col = 2
Duration_Trial(num2str('col'))_pp(num2str('row')) = length(data_stair_rise(row, col).VideoSignals)/data_stair_rise(row, col).VideoFrameRate; % expression after the '=' is not important.
What did I do wrong?

답변 (1개)

Star Strider
Star Strider 2014년 12월 27일

0 개 추천

You don’t need num2str. Just use ‘row’ and ‘col’ as they are:
Duration_Trial(col, _pp(row)) = length(data_stair_rise(row, col).VideoSignals)/data_stair_rise(row, col).VideoFrameRate;
I cannot follow what you are doing, but that change should at least get you closer to what you want.

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도움말 센터File Exchange에서 Data Type Identification에 대해 자세히 알아보기

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Sam
2014년 12월 27일

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2014년 12월 27일

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