Selection of priority data
조회 수: 3 (최근 30일)
이전 댓글 표시
Hello,
I'm trying to solve a problem. I have a vector of data such as:
data=[3;4;8;NaN;NaN;NaN;7;4;3;NaN;NaN;2;3;NaN;9]
length of data can be variable and NaN value phases can happen everywhere within a vector.
I need to find the first NaN value and count the number of next NaN. However, I do not want to take into account any other NaN value after the first portion of NaN.
In this case my result would be: First NaN at raw 4. Three NaN values. I know how to use the function find, indeed this is the code I used as far:
findNaN = find(isnan(data));
The problem is that in that way I will get the others NaN too that I do not want to locate.
Any idea?
Thanks, Giuseppe
댓글 수: 0
채택된 답변
Shoaibur Rahman
2014년 12월 27일
data=[3;4;8;NaN;NaN;NaN;7;4;3;NaN;NaN;2;3;NaN;9];
findNaN = find(isnan(data));
first = findNaN(1);
numberNaN = 1;
for k = first+1:length(data)
if isnan(data(k))
numberNaN = numberNaN+1;
else break
end
end
first, numberNaN
댓글 수: 0
추가 답변 (2개)
Image Analyst
2014년 12월 27일
If you're lucky enough to own the Image Processing Toolbox, it's easy. Just find the nan's, label then, and count the number in the first group. Here is the code:
labeledVector = bwlabel(isnan(data)) % Find nan's and label.
numberOfNansInFirstGroup = sum(labeledVector == 1) % Count the # of elements in group #1
댓글 수: 0
참고 항목
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!