Sort vector A according to vector B

I have two 14x1 vectors A and B. i am trying to sort A to match with B.

A = [0.9; 0.2; 0.4; 0.2; 0.3; 0.4; 0.7; 0.4; 0.1; 0.8; 0; 0; 0; 0];

B = [0; 0; 1; 1; 1; 1; 0; 0; 0; 0; 0; 0; 0; 0];

I am trying to make it so the 0's in A match with the 1's in B with a result of:

C = [0.9; 0.2; 0; 0; 0; 0; 0.4; 0.2; 0.3; 0.4; 0.7; 0.4; 0.1; 0.8]

This is my attempt:

TF1 = B(:,1)==1;

for j = 1:length(A)

n = j:length(B);

A(TF1,:) = 0

end

Any help would be appreciated. Thank you!

[Image Analyst]

Why? What's the use case (context, reason)? Is it homework?

How do I get help on homework questions on MATLAB Answers? - MATLAB Answers - MATLAB Central

Did you try a simple for loop with two counters to keep track of indexes?

[Aru E]

I am creating a program to automate a 2D truss solution. To solve for my reaction forces I need my displacement vector (A) to have the zeros lined up with my boundary conditions (B). I have not been able to successfully do this with a for loop or by sorting the vectors.

Answer 1

[Bruno Luong]

A = [0.9; 0.2; 0.4; 0.2; 0.3; 0.4; 0.7; 0.4; 0.1; 0.8; 0; 0; 0; 0];
B = [0; 0; 1; 1; 1; 1; 0; 0; 0; 0; 0; 0; 0; 0];

Ais0=A==0;
Bis1=B==1;
C=zeros(size(A));
C(Bis1)=A(Ais0);
C(~Bis1)=A(~Ais0);
C

C = 14×1

0.9000 0.2000 0 0 0 0 0.4000 0.2000 0.3000 0.4000