how to select an interval of certain hours each day within a larger timetable using timerange

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Kevin Johnson
Kevin Johnson 2022년 3월 26일
편집: Star Strider 2022년 3월 26일
Hi, I have a timetable of minute by minute data running over multiple days. I wish to identify the times outside regular business hours (9 am to 5 pm) in order to (later) process that data differently from the rest. How do I do this using the timerange function? In other words, how do I select a timerange within each day, for every day, without selecting any full days? Thanks

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Star Strider
Star Strider 2022년 3월 26일
Ran in:
The timerange function operates on timetable arrays, so to use it, the data must be in a timetable and the times must be duration arrays.
Use table2timetable for this if the data are not already in a timetable.
This uses table2timetable and duration array conversion —
DT = datetime('26-Mar-2022') + minutes(0:1440*2)'; % Two Days
Data = randn(numel(DT),3); % Create Other Values
T1 = [table(DT) array2table(Data)]
T1 = 2881×4 table
DT Data1 Data2 Data3 ____________________ __________ ________ ________ 26-Mar-2022 00:00:00 -0.6546 -0.31415 2.4173 26-Mar-2022 00:01:00 -0.20845 -0.89936 -2.3631 26-Mar-2022 00:02:00 -0.20717 0.55078 0.25069 26-Mar-2022 00:03:00 1.5701 -0.2149 -0.48116 26-Mar-2022 00:04:00 1.3051 -0.62446 0.89712 26-Mar-2022 00:05:00 -0.0059697 0.10382 0.90953 26-Mar-2022 00:06:00 -0.27235 1.0921 -0.53748 26-Mar-2022 00:07:00 1.5568 0.38122 1.2537 26-Mar-2022 00:08:00 -2.1977 1.0529 -1.6526 26-Mar-2022 00:09:00 1.9246 0.68009 -1.306 26-Mar-2022 00:10:00 -0.12461 0.48482 -1.4169 26-Mar-2022 00:11:00 -0.63642 0.081571 -0.11844 26-Mar-2022 00:12:00 0.92942 0.73651 -0.56618 26-Mar-2022 00:13:00 -0.17877 -0.33336 0.33599 26-Mar-2022 00:14:00 -0.41219 -0.85676 -0.80945 26-Mar-2022 00:15:00 0.13819 -0.17675 2.2606
TT1 = table2timetable(T1);
TT1.DT = duration(hour(TT1.DT),minute(TT1.DT),second(TT1.DT))
TT1 = 2881×3 timetable
DT Data1 Data2 Data3 ________ __________ ________ ________ 00:00:00 -0.6546 -0.31415 2.4173 00:01:00 -0.20845 -0.89936 -2.3631 00:02:00 -0.20717 0.55078 0.25069 00:03:00 1.5701 -0.2149 -0.48116 00:04:00 1.3051 -0.62446 0.89712 00:05:00 -0.0059697 0.10382 0.90953 00:06:00 -0.27235 1.0921 -0.53748 00:07:00 1.5568 0.38122 1.2537 00:08:00 -2.1977 1.0529 -1.6526 00:09:00 1.9246 0.68009 -1.306 00:10:00 -0.12461 0.48482 -1.4169 00:11:00 -0.63642 0.081571 -0.11844 00:12:00 0.92942 0.73651 -0.56618 00:13:00 -0.17877 -0.33336 0.33599 00:14:00 -0.41219 -0.85676 -0.80945 00:15:00 0.13819 -0.17675 2.2606
BusinessHours = timerange(hours(9), hours(17), 'closed'); % 09:00 To 17:00
TT1_BusinessHours = TT1(BusinessHours,:)
TT1_BusinessHours = 962×3 timetable
DT Data1 Data2 Data3 ________ ________ _________ _________ 09:00:00 -1.724 0.11354 -0.20664 09:01:00 -0.74624 -0.22058 -0.041664 09:02:00 1.2126 1.5414 1.0954 09:03:00 1.1506 0.4756 -1.3082 09:04:00 0.67332 0.95748 0.61051 09:05:00 1.5053 -0.35985 -0.13002 09:06:00 0.20755 -0.75411 -0.53651 09:07:00 -0.778 -0.96918 -0.28845 09:08:00 1.6209 -0.91014 0.40509 09:09:00 -0.59304 -0.0521 -0.59109 09:10:00 0.80869 -1.5248 -0.71053 09:11:00 0.84078 -0.055333 -0.36499 09:12:00 -0.96482 -0.62741 -0.49314 09:13:00 2.021 -0.95608 0.4493 09:14:00 0.1844 1.2234 0.14406 09:15:00 1.1104 0.38988 0.90148
OtherHours1 = timerange(hours(0),hours(9),'open'); % Midnight To 09:00
OtherHours2 = timerange(hours(17), hours(24), 'open'); % 17:00 To Midnight
TT1_OtherHours = [TT1(OtherHours1,:); TT1(OtherHours2,:)]
TT1_OtherHours = 1916×3 timetable
DT Data1 Data2 Data3 ________ __________ ________ ________ 00:01:00 -0.20845 -0.89936 -2.3631 00:02:00 -0.20717 0.55078 0.25069 00:03:00 1.5701 -0.2149 -0.48116 00:04:00 1.3051 -0.62446 0.89712 00:05:00 -0.0059697 0.10382 0.90953 00:06:00 -0.27235 1.0921 -0.53748 00:07:00 1.5568 0.38122 1.2537 00:08:00 -2.1977 1.0529 -1.6526 00:09:00 1.9246 0.68009 -1.306 00:10:00 -0.12461 0.48482 -1.4169 00:11:00 -0.63642 0.081571 -0.11844 00:12:00 0.92942 0.73651 -0.56618 00:13:00 -0.17877 -0.33336 0.33599 00:14:00 -0.41219 -0.85676 -0.80945 00:15:00 0.13819 -0.17675 2.2606 00:16:00 0.22279 -1.2399 -0.43212
Using timerange is not as straightforward as I thought it would be, and I had to ‘fractionate’ it to get it to work.
% figure
% plot(TT1_BusinessHours.DT, TT1_BusinessHours.Data1)
% figure
% plot(TT1_OtherHours.DT, TT1_OtherHours.Data1)
.
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Kevin Johnson
Kevin Johnson 2022년 3월 26일
Just tried running your code as is, but get an error message:
DT = datetime('26-Mar-2022') + minutes(0:1440*2)'; % Two Days
Data = randn(numel(DT),3); % Create Other Values
T1 = [table(DT) array2table(Data)];
TT1 = table2timetable(T1)
TT1.DT = duration(hour(TT1.DT),minute(TT1.DT),second(TT1.DT))
BusinessHours = isbetween(TT1.DT,hours(9),hours(17),'open'); % 09:00 To 17:00
TT1_BusinessHours = TT1(BusinessHours,:)
TT1_OtherHours = TT1(~BusinessHours,:)
"Unable to use a value of type 'datetime' as an index.
Error in untitled9 (line 23)
TT1.DT = duration(hour(TT1.DT),minute(TT1.DT),second(TT1.DT))"
Star Strider
Star Strider 2022년 3월 26일
편집: Star Strider 2022년 3월 26일
Ran in:
In MATLAB, indices must be integers greater than 0 or logical values.
I note that you are using R2019a and I (and the online Run feature here) are using R2022a. There very well could be version differences, however that line:
TT1.DT = duration(hour(TT1.DT),minute(TT1.DT),second(TT1.DT))
simply converts ‘TT1.DT’ into a duration array by extracting the hour, minute, and second from the datetime array to create it. Looking at the R2019a documentation, the duration and hour (and I assume the others) do not appear to have changed. I am at a loss to explain the inconsistency, or the error.
It runs correctly in my code, and since I can’t reproduce it, I can’t troubleshoot it.
Check to see that the arguments to the duration function are the simple integers it requires for each argument. Then, see if the duration call works with the same vectors. That’s the only approach I can think of to determine what the problem is.
EDIT — (26 Mar 2022 at 21:50)
The only other possibility that I can think of is that you have an ‘hour’, ‘minute’, or ‘second’ array that is overshadowing the MATLAB functions by those names.
Run:
which hour -all
/MATLAB/toolbox/matlab/timefun/hour.m /MATLAB/toolbox/matlab/datatypes/datetime/@datetime/datetime.m % Shadowed datetime method /MATLAB/toolbox/matlab/bigdata/@tall/hour.m % Shadowed tall method /MATLAB/toolbox/parallel/parallel/@codistributed/hour.m % Shadowed codistributed method
and do the same for each of the others. If the first entry in the output of that call is:
hour is a variable.
or something similar, that is the problem. The solution is to re-name the variable to something that makes sense in the context of the code, and does not overshadow any MATLAB functions.
.

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추가 답변 (1개)

Simon Chan
Simon Chan 2022년 3월 26일
Ran in:
Do you accept not using function timerange as follows?
T = readtable('date.txt')
T = 18×1 table
Var1 ___________________ 2015-11-08 12:00:00 2015-11-08 13:01:00 2015-11-08 14:02:00 2015-11-08 15:03:00 2015-11-08 17:00:00 2015-11-08 17:00:01 2015-11-08 18:04:00 2015-11-08 19:04:00 2015-11-08 20:05:00 2015-11-08 21:06:00 2015-11-08 22:07:00 2015-11-08 23:08:00 2015-11-09 00:09:00 2015-11-09 02:10:00 2015-11-09 07:10:00 2015-11-09 08:10:00
T.Var1(hour(T.Var1)<9 | hour(T.Var1)>=17 & ~(hour(T.Var1)>=17 & minute(T.Var1)==0 & second(T.Var1)==0))
ans = 11×1 datetime array
2015-11-08 17:00:01 2015-11-08 18:04:00 2015-11-08 19:04:00 2015-11-08 20:05:00 2015-11-08 21:06:00 2015-11-08 22:07:00 2015-11-08 23:08:00 2015-11-09 00:09:00 2015-11-09 02:10:00 2015-11-09 07:10:00 2015-11-09 08:10:00

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