How to use nested loop to produce the row and columns like that

조회 수: 3 (최근 30일)
Shuoze Xu
Shuoze Xu 2022년 3월 22일
댓글: Mathieu NOE 2022년 3월 22일
Given a 2D array, called A, of size 5 x 5,
Sample Output: Given A = [2,4,8,7,3;2,2,3,4,3;5,5,4,2,7;8,2,7,3,9;1,2,3,4,5];
output:
2 4 8 7 3
2 2 3
5 5 7
8 2 7 3 9
1 2 3 4 5
% My code
A = [2,4,8,7,3;2,2,3,4,3;5,5,4,2,7;8,2,7,3,9;1,2,3,4,5];
rows = size(A,1) % the number of rows in A
columns = size(A,2) % the number of columns in A
B = [];
for row = 1:rows
for column = 1:columns
if (row == 2 || row == 3)
if (column == 3 || column == 4)
B = [B A(i)]
end
end
end
end
disp(B);
My code is wrong i thought

채택된 답변

Mathieu NOE
Mathieu NOE 2022년 3월 22일
hello
seems to me B is simply A but rows 2 and 3 for columns 3 and 4 are empty (filled with NaN)
code :
A = [2,4,8,7,3;2,2,3,4,3;5,5,4,2,7;8,2,7,3,9;1,2,3,4,5];
B = A;
B(2:3,3:4) = NaN;
results :
A =
2 4 8 7 3
2 2 3 4 3
5 5 4 2 7
8 2 7 3 9
1 2 3 4 5
B =
2 4 8 7 3
2 2 NaN NaN 3
5 5 NaN NaN 7
8 2 7 3 9
1 2 3 4 5
  댓글 수: 4
Shuoze Xu
Shuoze Xu 2022년 3월 22일
Wow, it works.
Thank you so much

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추가 답변 (1개)

Arif Hoq
Arif Hoq 2022년 3월 22일
you did not clear your expection. you can try this
A = [2,4,8,7,3;2,2,3,4,3;5,5,4,2,7;8,2,7,3,9;1,2,3,4,5];
rows = size(A,1); % the number of rows in A
columns = size(A,2); % the number of columns in A
B = [];
for row = 1:rows
for column = 1:columns
% if row == 2 || row == 3 && column == 3 || column == 4
if (row == 2 || row == 3)
if (column == 3 || column == 4)
B = [B A(row)]
end
end
end
end
B = 2
B = 1×2
2 2
B = 1×3
2 2 5
B = 1×4
2 2 5 5
disp(B);
2 2 5 5
  댓글 수: 2
Shuoze Xu
Shuoze Xu 2022년 3월 22일
My expectation is to remove the elements in the third and fourth columns of the second row, and the third and fourth columns of the third row and print the array.
Shuoze Xu
Shuoze Xu 2022년 3월 22일
using the nested loop

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