How to attach multiple matrices to a single matrix?

There are A, B, C, and D matrices of 100x1 size.

I would like to combine this data into a matrix of 400x1 size.

However, the conditions must be followed by 5x1 of each matrix.

A = [1,2,3,4,5,6,7,8,9,10....]

B = [a,b,c,d,e,f,g,h,i,j...]

C = [11,22,33,44,55,66,77,88,99...]

D = [A,B,C,D,E,F,G,H,I,J...]

Assuming that it's like this,

F = [1,2,3,4,5,a,b,c,d,e,11,22,33,44,55,A,B,C,D,E,...]

I'm going to make these results.

The method I tried was:

Inside the for loop

Use the fseek function to add 'offset=0' first and then 'offset=5'.

I saved it using the spread function.

I got the result I wanted.

I'm wondering what else you can do.

Answer 1

[Davide Masiello]

The code below will keep repeating the values form each array 5 by 5, i.e. it won't use only the first 5 values of each array.

In the example below I used 1x15 arrays (I don't know what's after "z" in B and C). Just replace your array and it should work

clear,clc

A = 1:15

A = 1×15

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15

B = {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o'}

B = 1×15 cell array
    {'a'}    {'b'}    {'c'}    {'d'}    {'e'}    {'f'}    {'g'}    {'h'}    {'i'}    {'j'}    {'k'}    {'l'}    {'m'}    {'n'}    {'o'}

C = 11:11:165

C = 1×15

11 22 33 44 55 66 77 88 99 110 121 132 143 154 165

D = {'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O'}

D = 1×15 cell array
    {'A'}    {'B'}    {'C'}    {'D'}    {'E'}    {'F'}    {'G'}    {'H'}    {'I'}    {'J'}    {'K'}    {'L'}    {'M'}    {'N'}    {'O'}

A = reshape(A,5,[]);
B = reshape(B,5,[]);
C = reshape(C,5,[]);
D = reshape(D,5,[]);

OUT = [num2cell(A);B;num2cell(C);D];
OUT = OUT(:)'

OUT = 1×60 cell array
    {[1]}    {[2]}    {[3]}    {[4]}    {[5]}    {'a'}    {'b'}    {'c'}    {'d'}    {'e'}    {[11]}    {[22]}    {[33]}    {[44]}    {[55]}    {'A'}    {'B'}    {'C'}    {'D'}    {'E'}    {[6]}    {[7]}    {[8]}    {[9]}    {[10]}    {'f'}    {'g'}    {'h'}    {'i'}    {'j'}    {[66]}    {[77]}    {[88]}    {[99]}    {[110]}    {'F'}    {'G'}    {'H'}    {'I'}    {'J'}    {[11]}    {[12]}    {[13]}    {[14]}    {[15]}    {'k'}    {'l'}    {'m'}    {'n'}    {'o'}    {[121]}    {[132]}    {[143]}    {[154]}    {[165]}    {'K'}    {'L'}    {'M'}    {'N'}    {'O'}

Answer 2

[Arif Hoq]

A = [1,2,3,4,5,6,7,8,9,10];
B = {'a','b','c','d','e','f','g','h','i','j'};
C = [11,22,33,44,55,66,77,88,99,100];
D = {'A','B','C','D','E','F','G','H','I','J'};
idx=1:5;
out2=[A(idx) string(B(idx)) C(idx) string(D(idx))]

out2 = 1×20 string array
    "1"    "2"    "3"    "4"    "5"    "a"    "b"    "c"    "d"    "e"    "11"    "22"    "33"    "44"    "55"    "A"    "B"    "C"    "D"    "E"