Hello guys I want help .. I try to draw this signals in the pic attached , but the problem is, When i want to draw the ramp function, it starts on X-axis , but it should start from y=2 as the picture shown .. i attached my code too , any suggestions

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Seraj Mkb
Seraj Mkb 2022년 3월 16일
Here's the code
Walter Roberson
Walter Roberson 2022년 3월 16일
What does (2 minus ramp) look like?
Seraj Mkb
Seraj Mkb 2022년 3월 17일
Maybe the ramps will continue to -infinity ?
Consider:
sympref('HeavisideAtOrigin', 1)
ans = 
syms t
u = @(t) heaviside(t)
u = function_handle with value:
@(t)heaviside(t)
r = @(t) t
r = function_handle with value:
@(t)t
f = (u(t-0)-u(t-1.5)) * (2-r(t))
f = 
fplot(f, [-1 5] ); ylim([-1/2 2.5])
This is not exactly what you need: notice that at 1.5 it still has value 1/2. The plain ramp function has slope 1, and if you look at your graph, you need something with slope (0-2)/(1.5-0) = -4/3. I will leave it to you to figure out how you might get a slope of -4/3 for a ramp.

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