how to calculate cauchy product in summation
조회 수: 3 (최근 30일)
이전 댓글 표시
a(1)=1;
b(1)=1;
c(1)=1;
S=0;
Z=0;
for i=1:20
for p=1:i-1
a(i+1)=(1/(i+1)).*(a(i)-b(i));
b(i+1)=(1/(i+1)).*(a(i)-S-b(i));
c(i+1)=(1/(i+1))*(Z-c(i));
S=S+a(p)*c(i-p);
Z=Z+a(p)*b(i-p);
disp([S Z])
end
end
S ,Z are cauchy product how to calculate
댓글 수: 2
Ankit
2022년 3월 4일
what problem you are facing ?.. inside the loop you are trying to access the element which is not defined
a(i+1)=(1/(i+1)).*(a(i)-b(i));
답변 (1개)
Jan
2022년 3월 4일
The shown code cannot run. In the 1st iteration of the "for i" loop, the inner loop is not entered: "for p = 1:i-1". In the 2nd iteration i=2 the innerloop is entered and in the line
a(i+1)=(1/(i+1)).*(a(i)-b(i));
% ^^^ ^^^
The not existing elements a(2) and b(2) are requested.
Seeing only the failing code does not allow to suggest an improvement, because the readers have no chance to guess, what you want to do instead.
댓글 수: 3
Jan
2022년 3월 4일
편집: Jan
2022년 3월 4일
@shiv gaur: You have been asked repeatedly to use a proper code formatting. Please read an consider this: https://www.mathworks.com/matlabcentral/answers/help/rtc#rtc_summary . Thanks.
"pl see the runing program" - the code still stops with an error and we still cannot guess, what it should calculate.
"Resolve the problem" is not a polite way to ask for help, but a rough command. Refusing to post your code in a formatted way and posting not running code repeatedly let it look, like it is your intention to provoke the community.
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