Root LP problem is unbounded.

조회 수: 13 (최근 30일)
KRISHNA TEJA DUDE
KRISHNA TEJA DUDE 2022년 3월 1일
답변: Janardhan Rao Moparthi 2023년 12월 28일
p = optimproblem;
x = optimvar('x', 2,'Type','integer','LowerBound',0,'UpperBound',Inf);
p.ObjectiveSense = 'maximize';
p.Objective = 10*x(1) + 20*x(2);
cons1 = 6*x(1) + 8*x(2) >= 48;
cons2 = x(1) + 3*x(2) >=12;
p.Constraints.cons1 = cons1;
p.Constraints.cons2 = cons2;
sol = solve(p);
sol.x
Output ----
Solving problem using intlinprog.
Root LP problem is unbounded.
Intlinprog stopped because the root LP problem is unbounded.
ans =
[]

채택된 답변

Torsten
Torsten 2022년 3월 1일
Yes, I can see it with my naked eye that you can make the objective function as big as you like.
Take x(1) = 1e100, x(2) = 1e100, then x is feasible and the objective gives 30*1e100.

추가 답변 (1개)

Janardhan Rao Moparthi
Janardhan Rao Moparthi 2023년 12월 28일
Since you do not specify the boundaries for the variable x(1) and x(2), it is giving error. instead try
  1. if the variables are not binary
lb = zeros(2,1);
ub = [inf;inf];
2.If the variables are binary
lb = zeros(2,1);
ub = [1;1];

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