Timeit on pause(2) returns weird ouput

조회 수: 1 (최근 30일)
Torkel Loman
Torkel Loman 2022년 2월 28일
답변: Peter Perkins 2022년 3월 2일
I am trying to get the timeit function to work.I read https://uk.mathworks.com/help/matlab/ref/timeit.html and get the example:
X = rand(100);
f = @() svd(X);
t1 = timeit(f)
I want to try this using the pause(2), since this should take about 2 seconds:
g = @() pause(2);
t2 = timeit(g)
the output is
t2 =
3.4639e-06
which is a lot less than the expected 2 seconds. Clearly I am missunderstanding something (which probably makes my more serious attempts at using timeit also wrong), but what?

답변 (1개)

Peter Perkins
Peter Perkins 2022년 3월 2일
The issue is pause, not timeit:
"STATE = pause(...) returns the state of pause previous to processing the input arguments."
>> t2 = timeit(g,0)
t2 =
2.000208413333

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