Hello, I have two vectors x and y, both 601x1. I want to multiply them to form a matrix of 601x601, but the values inside the matrix have to be sqrt(x^2+y^2). How do I do this? Thanks.

 채택된 답변

Jan
Jan 2022년 2월 25일
편집: Jan 2022년 2월 25일

0 개 추천

z = sqrt(x .^ 2 + y.' .^ 2)
But, of course, this does not match "multiply them". If you want a multiplication:
x .* y.'
[EDITED] For Matlab versions < R2016b:
z = sqrt(bsxfun(@plus, x.'.^2, y.^2))

댓글 수: 2

Multiplication is not the right word, I agree. I've tried this and all I got is "Error using plus, Matrix dimensions must agree.".
Jan
Jan 2022년 2월 25일
See my comment under Walter's answer.

댓글을 달려면 로그인하십시오.

추가 답변 (2개)

KSSV
KSSV 2022년 2월 25일
x = rand(601,1) ;
y = rand(601,1) ;
iwant = sqrt(x.^2+y'.^2) ;
size(iwant)
ans = 1×2
601 601
Walter Roberson
Walter Roberson 2022년 2월 25일

1 개 추천

D = sqrt(x.'.^2 + y.^2)

댓글 수: 4

The difference between my answer and the nearly-simultaneous answers by @KSSV and @Jan is that I arranged for the x coordinates to run horizontally but they have the x coordinates run vertically.
I've tried this and all I got is "Error using plus, Matrix dimensions must agree.".
@Nikola Segedin: Which Matlab versionare you using? Since R2016b an "implicit expanding" is applied. For former versions:
D = sqrt(bsxfun(@plus, x.'.^2, y.^2))
I'm using R2010b. Thank you, this works for me!

댓글을 달려면 로그인하십시오.

카테고리

도움말 센터File Exchange에서 Logical에 대해 자세히 알아보기

제품

릴리스

R2010b

태그

질문:

2022년 2월 25일

편집:

Jan
2022년 2월 25일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by