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Problem multiplying exponential function with negative value

조회 수: 16 (최근 30일)
Hasib Ryan Rahman
Hasib Ryan Rahman 2022년 2월 11일
편집: Voss 2022년 2월 11일
I want to plot x(t) = t*(e−0.15t), − 20 ≤ t ≤ 20
I've tried:
t = -20:1:20;
x(t) = t.*(exp(-0.15*t));
Array indices must be positive integers or logical values.
plot(t,x(t))

채택된 답변

Voss
Voss 2022년 2월 11일
This statement
x(t) = t.*(exp(-0.15*t));
says to set the value of x at indexes given by t to the expression on the right-hand side. Indexes must be positive integers (1, 2, 3, ...), but t has some negative values and a zero value in it, so that's why the error happens.
In fact the syntax for what you want to do is slightly simpler. You can just say:
t = -20:1:20;
% no need to specify indexes into x, just set the whole thing:
x = t.*(exp(-0.15*t));
Then to plot:
plot(t,x)
  댓글 수: 1
Voss
Voss 2022년 2월 11일
편집: Voss 2022년 2월 11일
That makes t and x each vectors. Alternatively, you can make x a function of t if you want, and do the same thing:
x = @(t)t.*(exp(-0.15*t));
In this case the syntax x(t) evaluates the function x at the values of t given in t. Then your original syntax in the plot statement would be correct:
t = -20:1:20;
plot(t,x(t));

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추가 답변 (1개)

Yongjian Feng
Yongjian Feng 2022년 2월 11일
Try this:
t = -20:1:20;
x_t = t.*(exp(-0.15*t));
plot(t, x_t)

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