Removing additional points from scatter plot

How can I removed this additional legend data and keep only 2kw , 3kw and 4 kw and remove additional data points from legend of scatter plot ..Thank you in advance
The code That i used
A=xlsread('Compare_All_cases','B9:AB9');
i= 1
x1=ones(1,3);
y1=A(:,(i:(i+2)))
hold on
a=scatter(x1,y1,'filled','r')
xtics=[0:1:4];
xticlab={'' '20sec' '35sec' '50sec' ''};
set(gca,'XTick',xtics,'XTickLabel',xticlab,'Fontsize', 10)
text(x1(1),y1(1),sprintf(' (%.1f)[55 55]',y1(1)))
text(x1(2),y1(2),sprintf(' (%.1f)[55 35]',y1(2)))
text(x1(3),y1(3),sprintf(' (%.1f)[35 35]',y1(3)))
i= 4
x2=(ones(1,3)+1);
y2=A(:,(i:(i+2)))
hold on
scatter(x2,y2,'filled','r')
xtics=[0:1:4];
xticlab={'' '20sec' '35sec' '50sec' ''};
set(gca,'XTick',xtics,'XTickLabel',xticlab,'Fontsize', 10)
text(x2(1),y2(1),sprintf(' (%.1f)[55 55]',y2(1)))
text(x2(2),y2(2),sprintf(' (%.1f)[55 35]',y2(2)))
text(x2(3),y2(3),sprintf(' (%.1f)[35 35]',y2(3)))
i= 7
x3=(ones(1,3)+2);
y3=A(:,(i:(i+2)))
hold on
scatter(x3,y3,'filled','r')
xtics=[0:1:4];
xticlab={'' '20sec' '35sec' '50sec' ''};
set(gca,'XTick',xtics,'XTickLabel',xticlab,'Fontsize', 10)
text(x3(1),y3(1),sprintf(' (%.1f)[55 55]',y3(1)))
text(x3(2),y3(2),sprintf(' (%.1f)[55 35]',y3(2)))
text(x3(3),y3(3),sprintf(' (%.1f)[35 35]',y3(3)))
i= 10
x4=(ones(1,3));
y4=A(:,(i:(i+2)))
hold on
scatter(x4,y4,'filled','b')
xtics=[0:1:4];
xticlab={'' '20sec' '35sec' '50sec' ''};
set(gca,'XTick',xtics,'XTickLabel',xticlab,'Fontsize', 10)
text(x4(1),y4(1),sprintf(' (%.1f)[55 55]',y4(1)))
text(x4(2),y4(2),sprintf(' (%.1f)[55 35]',y4(2)))
text(x4(3),y4(3),sprintf(' (%.1f)[35 35]',y4(3)))
i= 13
x5=(ones(1,3)+1);
y5=A(:,(i:(i+2)))
hold on
scatter(x5,y5,'filled','b')
xtics=[0:1:4];
xticlab={'' '20sec' '35sec' '50sec' ''};
set(gca,'XTick',xtics,'XTickLabel',xticlab,'Fontsize', 10)
text(x5(1),y5(1),sprintf(' (%.1f)[55 55]',y5(1)))
text(x5(2),y5(2),sprintf(' (%.1f)[55 35]',y5(2)))
text(x5(3),y5(3),sprintf(' (%.1f)[35 35]',y5(3)))
i= 16
x6=(ones(1,3)+2);
y6=A(:,(i:(i+2)))
scatter(x6,y6,'filled','b')
hold on
xtics=[0:1:4];
xticlab={'' '20sec' '35sec' '50sec' ''};
set(gca,'XTick',xtics,'XTickLabel',xticlab,'Fontsize', 10)
text(x6(1),y6(1),sprintf(' (%.1f)[55 55]',y6(1)))
text(x6(2),y6(2),sprintf(' (%.1f)[55 35]',y6(2)))
text(x6(3),y6(3),sprintf(' (%.1f)[35 35]',y6(3)))
i= 19
x7=(ones(1,3));
y7=A(:,(i:(i+2)))
hold on
scatter(x7,y7,'filled','k')
xtics=[0:1:4];
xticlab={'' '20sec' '35sec' '50sec' ''};
set(gca,'XTick',xtics,'XTickLabel',xticlab,'Fontsize', 10)
text(x7(1),y7(1),sprintf(' (%.1f)[55 55]',y7(1)))
text(x7(2),y7(2),sprintf(' (%.1f)[55 35]',y7(2)))
text(x7(3),y7(3),sprintf(' (%.1f)[35 35]',y7(3)))
i= 22
x8=(ones(1,3)+1);
y8=A(:,(i:(i+2)))
hold on
scatter(x8,y8,'filled','k')
xtics=[0:1:4];
xticlab={'' '20sec' '35sec' '50sec' ''};
set(gca,'XTick',xtics,'XTickLabel',xticlab,'Fontsize', 10)
text(x8(1),y8(1),sprintf(' (%.1f)[55 55]',y8(1)))
text(x8(2),y8(2),sprintf(' (%.1f)[55 35]',y8(2)))
text(x8(3),y8(3),sprintf(' (%.1f)[35 35]',y8(3)))
i= 25
x9=(ones(1,3)+2);
y9=A(:,(i:(i+2)))
hold on
scatter(x9,y9,'filled','k')
xtics=[0:1:4];
xticlab={'' '20sec' '35sec' '50sec' ''};
set(gca,'XTick',xtics,'XTickLabel',xticlab,'Fontsize', 10)
text(x9(1),y9(1),sprintf(' (%.1f)[55 55]',y9(1)))
text(x9(2),y9(2),sprintf(' (%.1f)[55 35]',y9(2)))
text(x9(3),y9(3),sprintf(' (%.1f)[35 35]',y9(3)))
xlim([0 4])
ylabel('CO emissions [mg]')
title ('CO emission for 25 sec after catalyst 1')
legend('2 kW' ,'' ,'' ,'3 kW' ,'','','4 kW')

댓글 수: 6

Rik
Rik 2022년 2월 11일
Why aren't you using a loop? Then it would also be easier to create an array of handles you can use in your call to legend.
Prasad Joshi
Prasad Joshi 2022년 2월 11일
편집: Prasad Joshi 2022년 2월 11일
Actaully Values are not in same order so not using for loop . as you can easy carefully its first taking first 3 values and in one line then 10 ,11,12 in same one line and next 19,20 21 in same line ....like all come under 20 sec duration .......so for loop cant be implemented here I feel so that why ....do you have any other suggestion how can I implement ...any changes in code you can suggest ...Thank you ...
Rik
Rik 2022년 2월 11일
I don't see where anything is in a different order. The only thing I see is that you could have your loop variable grow with step size 3. Can you point out where there is an anomaly?
just see i= 1 & i= 10 i=19
x1=ones(1,3);
this 3 cases come in same line i.e 20 sec duration
They all depend on A directly: A(:,i:(i+2)). There is nothing in the code that suggests anything is different. You only use numbered variables, that is the only difference I see.
Apart from the line that defines the value of i and the numbered variables, what is the difference?
Below I have interleave two of the examples you mention. Where exactly is the difference?
i= 1
i= 10
x1=ones(1,3);
x4=(ones(1,3));
y1=A(:,(i:(i+2)))
y4=A(:,(i:(i+2)))
hold on
hold on
a=scatter(x1,y1,'filled','r')
scatter(x4,y4,'filled','b')
xtics=[0:1:4];
xtics=[0:1:4];
xticlab={'' '20sec' '35sec' '50sec' ''};
xticlab={'' '20sec' '35sec' '50sec' ''};
set(gca,'XTick',xtics,'XTickLabel',xticlab,'Fontsize', 10)
set(gca,'XTick',xtics,'XTickLabel',xticlab,'Fontsize', 10)
text(x1(1),y1(1),sprintf(' (%.1f)[55 55]',y1(1)))
text(x4(1),y4(1),sprintf(' (%.1f)[55 55]',y4(1)))
text(x1(2),y1(2),sprintf(' (%.1f)[55 35]',y1(2)))
text(x4(2),y4(2),sprintf(' (%.1f)[55 35]',y4(2)))
text(x1(3),y1(3),sprintf(' (%.1f)[35 35]',y1(3)))
text(x4(3),y4(3),sprintf(' (%.1f)[35 35]',y4(3)))
Actually I am not that much proficient in Programming a beginner .....I am just seeing from online stuffs and developing code ...can you suggest how can I add for loop to this case ...Thank you in advance

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답변 (1개)

Prasad Joshi
Prasad Joshi 2022년 2월 11일

0 개 추천

Just in cases anyone requiried add duplicate entries to code ...it work for me
hold on
h1 = scatter(-10,-10, 'r,'filled', 'DisplayName', ' 2kW');
h2 = scatter(-10,-10, 'b','filled', 'DisplayName', '3 kW');
h3 = scatter(-10,-10, 'k','filled', 'DisplayName', '4 kW');
% duplicating the plot
xlim([0 10] ) % taking positive values
legend([h1(1) h2(1) h3(1)])

댓글 수: 2

Rik
Rik 2022년 2월 11일
Note that this is exactly what I suggested in my initial comment.
ya ...Thank you RIK for you help ......

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