In addition to the point on the graph that shows up, I'd like to also have the line of the equation show up on the graph as well. I have tried using hold on and hold off and a couple other ways, but I cannot figure it out
prompt = 'Time of flight? (s) ';
t = input(prompt);
if (t <= 45)
h = 15*t.^2;
fprintf('Altitude: %dm\n\n', h)
v = 30*t;
fprintf('Velocity: %dm/s\n\n', v);
figure(1)
subplot(2,1,1)
plot(t, h, 'o'), xlabel('Time (s)'), ylabel('Altitude (m)'), title('Altitude vs Time')
subplot(2,1,2)
plot(t, v,'o'), xlabel('Time (s)'), ylabel('Velocity (m/s)'), title('Velocity vs Time')
elseif (t < 117.5)
h = 30375 + (1350*t) + 0.5*(-11.5)*t.^2;
fprintf('Altitude: %dm\n\n', h )
v = 1350 - 11.5*t;
fprintf('Velocity: %dm/s\n\n', v);
figure(2)
subplot(2,1,1)
plot(t, h,'o'), xlabel('Time (s)'), ylabel('Altitude (m)'), title('Altitude vs Time')
subplot(2,1,2)
plot(t, v,'o'), xlabel('Time (s)'), ylabel('Velocity (m/s)'), title('Velocity vs Time')
end

 채택된 답변

Davide Masiello
Davide Masiello 2022년 2월 4일

1 개 추천

prompt = 'Time of flight? (s) ';
t = input(prompt);
tx = t-5:t+5;
if (t <= 45)
h = @(x) 15*x.^2;
fprintf('Altitude: %dm\n\n', h(t))
v = @(x) 30*x;
fprintf('Velocity: %dm/s\n\n', v(t));
figure(1)
subplot(2,1,1)
plot(t,h(t),'o',tx,h(tx)), xlabel('Time (s)'), ylabel('Altitude (m)'), title('Altitude vs Time')
subplot(2,1,2)
plot(t,v(t),'o',tx,v(tx)), xlabel('Time (s)'), ylabel('Velocity (m/s)'), title('Velocity vs Time')
elseif (t < 117.5)
h = @(x) 30375 + (1350*x) + 0.5*(-11.5)*x.^2;
fprintf('Altitude: %dm\n\n', h(t))
v = @(x) 1350 - 11.5*x;
fprintf('Velocity: %dm/s\n\n', v(t));
figure(2)
subplot(2,1,1)
plot(t,h(t),'o',tx,h(tx)), xlabel('Time (s)'), ylabel('Altitude (m)'), title('Altitude vs Time')
subplot(2,1,2)
plot(t,v(t),'o',tx,v(tx)), xlabel('Time (s)'), ylabel('Velocity (m/s)'), title('Velocity vs Time')
end

댓글 수: 2

Awesome! Thanks for your help. Would you be able to explain what you did on line 3?
I just created a vector of times that spans around your input time.
If the code works and you are satisfied with the answer, please accept it. I will reply to any further questions anyways.

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