Delete Cells in Cell array in two loops....

Hi everyone,

I have the following code and want to delete the empty cells in the results:

tt1 = find(year(Time) == 2015 & month(Time) == 10); 
tt2 = find(year(Time) == 2010 & month(Time) == 10);
tt3 = find(year(Time) == 2019 & month(Time) == 04);

JT = [  tt1; tt2; tt3  ];
H= [ 4, 8];
for h = H
    for jt = JT'
        PdfDat{h,jt+h}=strcat('T',num2str(year(Time(jt+h))), 'Q', num2str(ceil(month(Time(jt+h)) / 3)));
        Pdfd{h,jt+h}=ResMatch_LU.PST(jt+h, :);
    end 
end 

The results are the following in which I want to delete the [ ] such that the array will be presented in fucntion of 'h' and 'jt+h' :

I want also to delete [ ] in the cell "1x401 double" here in coulumns 52 and 56;

Could you please help me to do those changes? My Matlab version is R2015a.

Many thanks!

Answer 1

[Ankit]

You can use cellfun: Apply a function to each cell of a cell array

'isempty' -- true for cells containing an empty array, false otherwise

PdfDat_new = PdfDat(~cellfun('isempty',PdfDat));
Pdfd_new = Pdfd(~cellfun('isempty',Pdfd));

[Ibrahs]

Thank you Ankit

Your code lines provide the below results, wile I want that those results be presented in function of "h". In other words, I need to have 2 cells of (3x1 cell) for each "H" instead of the below 6x1 cells. How to do that?

I want that for each H , we have :

[Ankit]

You can achieve that by reshape.

PdfDat_new = reshape(PdfDat(~cellfun('isempty',PdfDat)),2,[])'; 
PdfDat_new1 = out(:,1); % 3x1 cell 
PdfDat_new2 = out(:,2); % 3x1 cell

[Ibrahs]

Thank you Ankit,

I got the following error with reshape:

Also, I don't have the "out ()" function with my R2015a version.

When I correctly use "Reshape", PdfDat_new = reshape(PdfDat(~cellfun('isempty',PdfDat)),[],1)';

I am getting the following cells which should not be split uniformly in two cells, rather I need to have here

PdfDat_new1 = [PdfDat_new(1,1), PdfDat_new(1,3), PdfDat_new(1,5)];

PdfDat_new2 = [PdfDat_new(1,2), PdfDat_new(1,4), PdfDat_new(1,6)];

These cells are in function of "H".

How can I do that? And how can I overcome the issue with the function "Out"?

Many thanks again

[Ankit]

PdfDat_new1 = PdfDat_newout(1:2:5,:);
PdfDat_new2 = PdfDat_newout(2:2:6,:);

You can also use for loop and other ways to achieve as per your requirement

[Rik]

You should avoid numbered variables. It sounds like the number of PdfDat_new variables can change. If you can't guarantee that there will only be exactly 2, you should consider putting them in a cell array so you can index them in a loop.

[Ibrahs]

Hi Rik,

Yu are right. I should avoid numbering variables as I know that the cells coming from H will not be exactly 2.

I am still looking for the solution, but i am stuck.

Would anyone help me?

Thank you.

[Ankit]

why dont you use the method mentioned by rik? here with limited info and without having your relevant file it is not easy to reproduce the same problem

[Rik]

It would probably help if you replace this loop:

for h=H

with this loop:

for n_H=1:numel(H)
    h=H(n);
    
    ...
    
    PdfDat_new{n_H}=...