How to plot a function dependent on no. of iterations, provided it plots till nth iteration where n is the number where the function is converged?

조회 수: 9 (최근 30일)
Hello All,
I am trying to plot a function vs no. of iterations. In the for loop, i have given the convergence condition, but I am unable to plot for f(x) vs no. iterations (till convergence). Please help.
Its of the form:
for m=1:n
pu(m)=(-1)^m)/((2*m)+1))*(exp(-((2*m)+1)))
e = e+pu;
if (abs(pu)/e)<(10^(-6)) %convergence check
break
end
end
hold all
plot(1:n,pu,'linestyle','none','marker','*')

채택된 답변

VBBV
VBBV 2022년 1월 28일
편집: VBBV 2022년 1월 29일
n= 10;
e = 0;
for m=1:n
pu(m)=(-1)^m/((2*m)+1)*(exp(-((2*m)+1)))
e = e+pu(m);
if (abs(pu(m))/e)>(10^(-6)) %convergence check
break
end
end
pu = -0.0166
pu = 1×2
-0.0166 0.0013
pu = 1×3
-0.0166 0.0013 -0.0001
pu = 1×4
-0.0166 0.0013 -0.0001 0.0000
pu = 1×5
-0.0166 0.0013 -0.0001 0.0000 -0.0000
pu = 1×6
-0.0166 0.0013 -0.0001 0.0000 -0.0000 0.0000
pu = 1×7
-0.0166 0.0013 -0.0001 0.0000 -0.0000 0.0000 -0.0000
pu = 1×8
-0.0166 0.0013 -0.0001 0.0000 -0.0000 0.0000 -0.0000 0.0000
pu = 1×9
-0.0166 0.0013 -0.0001 0.0000 -0.0000 0.0000 -0.0000 0.0000 -0.0000
pu = 1×10
-0.0166 0.0013 -0.0001 0.0000 -0.0000 0.0000 -0.0000 0.0000 -0.0000 0.0000
hold all
plot(1:n,pu,'linestyle','-','marker','.')
Check the convergence condition
  댓글 수: 7
VBBV
VBBV 2022년 1월 29일
legend(mrkr{cidx},legendInfo)
Put this line inside the inner for loop. After legendInfo. Everytime the inner for loop exits, it's over written with initial values for mrkr and clr index.
VBBV
VBBV 2022년 1월 29일
편집: VBBV 2022년 1월 29일
u=zeros(n,npoints); % change also This line in beginning
u(m,cidx)=pu(m);
hold all
plot(1:m,u(1:m,cidx),'linestyle','none','marker',mrkr{cidx},'Color',clr{cidx})
You also need to change these two lines inside the for loop. As you can see the u value is dependent on pu which is again varying with each outer iteration of for loop.

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 General Applications에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by