computing a interpolating polynomial for some function

조회 수: 1 (최근 30일)
Anas Gharsa
Anas Gharsa 2022년 1월 26일
댓글: Steven Lord 2022년 1월 26일
I am trying to understand how to use the commands polyfit and polyval so i am trying to interpolate some function, I wrote something so simple but even it is simple it gives me error
x=linspace(-1,1,20);
y= @(x) 1/(1+16*(x^2));
p = polyfit (x,y,2);
plot(x,p)
and this is the error message
Error using polyfit (line 48)
The first two inputs must have the same number of elements.
Error in polyfit_polyval (line 7)
p = polyfit (x,y,2);

채택된 답변

Torsten
Torsten 2022년 1월 26일
편집: Torsten 2022년 1월 26일
x = linspace(-1,1,20);
yfunc = @(x) 1./(1+16*x.^2);
y = yfunc(x);
...
or
x=linspace(-1,1,20);
y=1./(1+16*x.^2);
...
  댓글 수: 9
Anas Gharsa
Anas Gharsa 2022년 1월 26일
i understand now!! Thank you once again
Steven Lord
Steven Lord 2022년 1월 26일
In your original code, the main problem was that y was a function handle but polyfit requires its first two inputs to be numeric arrays of the same size. Note that Torsten defined the function not as y but as yfunc then evaluated yfunc with x as the input to generate y. So the data that got passed into polyfit as its second input was the result of evaluating that function at the points in x rather than the function.
The use of the element-wise operators allowed the function to be evaluated on an array and return an array with the same size. The matrix form of the operator would require the inputs to be square matrices.
A = [1 2; 3 4]
A = 2×2
1 2 3 4
y = A.*A % each element of y is the square of the corresponding element of A
y = 2×2
1 4 9 16
z = A*A % this perform matrix multiplication instead of element-wise
z = 2×2
7 10 15 22

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Polynomials에 대해 자세히 알아보기

제품


릴리스

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by