Substitute variables in function handle

Hello,

I have two implementations.

1. Create functions based on the parameter
2. Pass this functions to another function and evaluate them there

I'm creating functions like this:

for i=1:n/2-1    
    funk{i} = @(x)2*x(i)-2+400*x(i)^3-400*x(i)*x(i+1);
end 

I want this to create multiple functions (depends on n) with i to be superset by a number, but WITHOUT being solved right away as i want to hand it over to another function in which this should get solved.

How can I achieve this?

Thanks in advance

[KSSV]

You can try:

funk = @(xi1,xi2)2*xi1-2+400*xi1^3-400*xi1*xi2;

Answer 1

[Walter Roberson]

What you have already done should work.

Although all of the function handles will look the same, they would have captured different values of i

For example,

for i = 1 : 2
    funk{i} = @(x)2*x(i)-2+400*x(i)^3-400*x(i)*x(i+1);
end

ws1 = functions(funk{1}).workspace{1}

ws1 = struct with fields:
    i: 1

ws2 = functions(funk{2}).workspace{1}

ws2 = struct with fields:
    i: 2

Notice how the information embedded within the function handles funk{1} and funk{2} is different -- they have different embedded i values.

[Clueless]

So I can simply pass this to another function like:

for i = 1 : 2
    funk{i} = @(x)2*x(i)-2+400*x(i)^3-400*x(i)*x(i+1);
end
function test(fun)
test(funk)

This returns an error that Array indices must be positive integers or logical values in my implementation of the calling function.

[Torsten]

x = [1 2 3 4 5 6];
for i = 1 : 2
    funk{i} = @(x)2*x(i)-2+400*x(i)^3-400*x(i)*x(i+1);
end
test(funk,x)

function test(fun,x)
  fun{1}(x)
  fun{2}(x)
end