Dear all
I am unable to for a helix spiral using attached code.
First i want to mirror the generated curve in opposite direction and then i want a helix spiral to be formed with certain height and with certain gap. The gap can be taken as 0.5 and height as 60 mm.
The code is attached below.
Thank you
clc
R=30; %% radius of curvature
W=0.0125; %% width of grating
r=10; %% radius of workpiece
th_1=(asin(W/R)); %% angle at which blazed grating existd
th_2=2*(asin(r/R)); %% angle at which primary profile exists
n=round(degr_2/degr); %% number of grating
for i=1:n
th (i)= (((i*th_1)-((th_2)/2)));
x(i)= -(R*cos(th (i)));
z(i)= (R*sin(th (i)));
end
X1=x;
Z1=z;
figure (1)
plot(X1,Z1); hold on

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Voss
Voss 2022년 1월 13일
편집: Voss 2022년 1월 13일

0 개 추천

clc
R=30; %% radius of curvature
W=0.0125; %% width of grating
r=10; %% radius of workpiece
th_1=(asin(W/R)); %% angle at which blazed grating existd
th_2=2*(asin(r/R)); %% angle at which primary profile exists
% n=round(degr_2/degr); %% number of grating
n = 1e5;
for i=1:n
th (i)= (((i*th_1)-((th_2)/2)));
x(i)= -(R*cos(th (i)));
z(i)= (R*sin(th (i)));
end
X1=x;
Z1=z;
Y1=th;
figure (1)
% plot(X1,Z1); hold on
plot3(X1,Y1,Z1);
xlabel('x');
ylabel('th');
zlabel('z');
view([30 60])

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Kundan Prasad
Kundan Prasad 2022년 1월 13일
i want to maintain of gap of 0.5 within every revolution till the height of 60 how it can be done??
clc
R=30; %% radius of curvature
W=0.0125; %% width of grating
r=10; %% radius of workpiece
th_1=(asin(W/R)); %% angle at which blazed grating existd
th_2=2*(asin(r/R)); %% angle at which primary profile exists
% n=round(degr_2/degr); %% number of grating
n = (2*pi/th_1)*120;
for i=1:n
th(i) = i*th_1 - th_2/2;
x(i)= -R*cos(th(i));
z(i)= R*sin(th(i));
end
X1=x;
Z1=z;
Y1=th./(240*pi-th_2/2)*60;
figure (1)
% plot(X1,Z1); hold on
plot3(X1,Y1,Z1);
xlabel('x');
ylabel('th');
zlabel('z');
view([30 60])

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