Error in using eval statement
조회 수: 2 (최근 30일)
이전 댓글 표시
Why it shows an incomplete statement ?
I'm trying to write this statement using eval as follows : Energy_H_A1S1 = rms (H_A1S1); but in eval it shows error ?
Thanks in advance.
eval(['Energy_H_A',num2str(1),'S',num2str(1),' = rms(H_A',num2str(1),'S',num2str(1);]);
댓글 수: 2
Stephen23
2022년 1월 10일
편집: Stephen23
2022년 1월 10일
"I'm trying to write this statement using eval as follows : Energy_H_A1S1 = ..."
And that is the start of your problems.
Forcing meta-data into variable names makes acessing your data complex, slow, inefficient, and buggy... as your question demonstrates. Meta-data is data. Data should be stored in variables, not in variable names.
Your poor data design forces you into writing bad code, which could be easily avoided by storing the meta-data correctly.
채택된 답변
Paul
2022년 1월 10일
There's almost certainly a better way to organize the data and store the results, but if you must use eval:
['Energy_H_A',num2str(1),'S',num2str(1),' = rms(H_A',num2str(1),'S',num2str(1);]
should be:
['Energy_H_A',num2str(1),'S',num2str(1),' = rms(H_A',num2str(1),'S',num2str(1),');']
댓글 수: 4
Stephen23
2022년 1월 10일
편집: Stephen23
2022년 1월 10일
"Could you please also post an example of the mentioned better way instead of eval as it takes high running time for this varying A1..4..S1..4 data"
The MATLAB introductory tutorials also show how to use MATLAB effectively by using arrays and indexing:
추가 답변 (1개)
Walter Roberson
2022년 1월 10일
Asking how to use eval without problems is like asking how to use a chainsaw without its chain guard. It would be irresponsible for us to answer in any way other than "Don't do that!"
참고 항목
카테고리
Help Center 및 File Exchange에서 Logical에 대해 자세히 알아보기
제품
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!