How to reshape matrix without repeating values of matrix?

Hi, For example we have a matrix 4 x 2 and we have to rearrange matrix such that

columns

rows 2 5 % 2 can pair with any below value except 5 or 5 can pair with any value except 2

4 3 % 4 can pair any value below except 3 and above pair

1 6 % 1 can pair with any below value except 6 and above pairs

7 8 % 7 can pair with any below value except 8 and above pairs ( as in this case only one value will be

remains)

This logic should work on any [] x 2 matrix.

Thanks and Regards,

Sandeep

Answer 1

[KSSV]

A = [2     5
     4     3
     1     6
     7     8];

[m,n] = size(A) ; 
iwant = zeros(m,m) ; 
iwant(:,1) = A(:,1) ; 
for i = 1:m
    idx = setdiff(1:m,i) ; 
    iwant(i,2:end) = A(idx,2)' ;
end
iwant

iwant = 4×4

2 3 6 8 4 5 6 8 1 5 3 8 7 5 3 6

[SANDEEP SINGH RANA]

The return matrix should be 4 x 2. In the above method, if i select any two column ( say 1,2), then 5 is repeating. And if i select any two rows then, values are pairing with it self.

Initial given matrix:

columns

rows 2 5

4 3

1 6

7 8

The matrix which i want or expected is

columns

rows 2 3/1/6/7/8 (any value but not 5) (let i select 6)

4 5/1/7/8 (any value but not 3, (2,6)) (let I select 8)

1 3/5/7 (any value but not 6,(2,6),(4,8)) (let I select 5)

7 3 (only one value left )

So the above matrix look like:

columns

rows 2 6

4 8

1 5

7 3

[KSSV]

I gave you all the options possible...pick any randmoly...easy:

A = [2     5
     4     3
     1     6
     7     8];

[m,n] = size(A) ; 
iwant = zeros(m,2) ; 
iwant(:,1) = A(:,1) ; 
for i = 1:m
    idx = randsample(setdiff(1:m,i),1) ;
    
    iwant(i,2) = A(idx,2) ;
end
iwant

iwant = 4×2

2 8 4 8 1 5 7 5

[SANDEEP SINGH RANA]

In this matrix, 2 is pair with 8 and 4 is also pairing with 8. This is not required.