What's the problem with this runge kutta code ?
for this parametrs (71,1000,8,10,pi/6,0,0,0.1,10)
function [Theta,r]=test3rk4(m,k,l_0,R1,A1,R2,A2,h,t_end)
t=0:h:t_end;
% A1 = zeros(1,numel(t)) % A2 = A1; R1 = A1; R2 = A1;
% R1 = zeros(1,numel(t))
g=9.81;
f1=@(A2) A2;
f2=@(A1,A2,R1,R2) -2*(R2./R1).*A2-g*sin(A1);
f3=@(R2) R2;
f4=@(A1,A2,R1) R1.*(A2.*A2)+g*cos(A1)-k*(R1-l_0)/m;
for i=1:(length(t)-1)
k11=h*f1(A2(i));
k12=h*f2(A1(i),A2(i),R1(i),R2(i));
k13=h*f3(R2(i));
k14=h*f4(A1(i),A2(i),R1(i));
k21=h*f1((A2(i)+k12/2));
k22=h*f2((A1(i)+k11/2),(A2(i)+k12/2),(R1(i)+k13/2),(R2(i)+k14/2));
k23=h*f3((R2(i)+k14/2));
k24=h*f4((A1(i)+k11/2),(A2(i)+k12/2),(R1(i)+k13/2));
k31=h*f1((A2(i)+k22/2));
k32=h*f2((A1(i)+k21/2),(A2(i)+k22/2),(R1(i)+k23/2),(R2(i)+k24/2));
k33=h*f3((R2(i)+k24/2));
k34=h*f4((A1(i)+k21/2),(A2(i)+k22/2),(R1(i)+k23/2));
k41=h*f1((A2(i)+k32));
k42=h*f2((A1(i+1)),(A2(i)+k32),(R1(i)+k33),(R2(i)+k34));
k43=h*f3((R2(i)+k34));
k44=h*f4((A1(i)),(A2(i)+k32),(R1(i)+k33));
A1(i+1) = A1(i) + (k11+2*k21+2*k31+k41)/6;
A2(i+1) = A2(i) + (k12+2*k22+2*k32+k42)/6;
R1(i+1) = R1(i) + (k13+2*k23+2*k33+k43)/6;
R2(i+1) = R2(i) + (k14+2*k24+2*k34+k44)/6;
end
Theta=A1;
r=R1;
subplot(2,2,1)
plot(t,A1,'LineWidth',1)
title('theta vs t')
xlabel('t','fontsize',14,'fontweight','bold')
ylabel('Theta','fontsize',14,'fontweight','bold')
subplot(2,2,2)
plot(t,R1,'LineWidth',1)
xlabel('t','fontsize',14,'fontweight','bold')
ylabel('r','fontsize',14,'fontweight','bold')
subplot(2,2,[3,4])
x=R1.*sin(A1)
y=-R1.*cos(A1)
plot(x,y)
end

댓글 수: 3

John D'Errico
John D'Errico 2022년 1월 2일
When you edit away your question, you are being rude to the person who spent their time answering your question. You make it impossible for others to get help from that same problem. Someone else might be able to learn something. Now your question is useless to others.
If your plan was to do exactly this, then you should never ask the question in the first place.
Rena Berman
Rena Berman 2022년 1월 25일

(Answers Dev) Restored edit

James Tursa
James Tursa 2022년 1월 31일
k42 and k44 do not have the correct A1 terms.

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답변 (2개)

Walter Roberson
Walter Roberson 2022년 1월 2일

1 개 추천

k42=h*f2((A1(i+1)),(A2(i)+k32),(R1(i)+k33),(R2(i)+k34));
That line requires that A1(i+1) exists before A1(i+1) has been assigned to.
[t,r] = test3rk4(71,1000,8,10,pi/6,0,0,0.1,10)
Index exceeds the number of array elements. Index must not exceed 1.

Error in solution>test3rk4 (line 29)
k42=h*f2((A1(i+1)),(A2(i)+k32),(R1(i)+k33),(R2(i)+k34));
function [Theta,r]=test3rk4(m,k,l_0,R1,A1,R2,A2,h,t_end)
t=0:h:t_end;
% A1 = zeros(1,numel(t)) % A2 = A1; R1 = A1; R2 = A1;
% R1 = zeros(1,numel(t))
g=9.81;
f1=@(A2) A2;
f2=@(A1,A2,R1,R2) -2*(R2./R1).*A2-g*sin(A1);
f3=@(R2) R2;
f4=@(A1,A2,R1) R1.*(A2.*A2)+g*cos(A1)-k*(R1-l_0)/m;
for i=1:(length(t)-1)
k11=h*f1(A2(i));
k12=h*f2(A1(i),A2(i),R1(i),R2(i));
k13=h*f3(R2(i));
k14=h*f4(A1(i),A2(i),R1(i));
k21=h*f1((A2(i)+k12/2));
k22=h*f2((A1(i)+k11/2),(A2(i)+k12/2),(R1(i)+k13/2),(R2(i)+k14/2));
k23=h*f3((R2(i)+k14/2));
k24=h*f4((A1(i)+k11/2),(A2(i)+k12/2),(R1(i)+k13/2));
k31=h*f1((A2(i)+k22/2));
k32=h*f2((A1(i)+k21/2),(A2(i)+k22/2),(R1(i)+k23/2),(R2(i)+k24/2));
k33=h*f3((R2(i)+k24/2));
k34=h*f4((A1(i)+k21/2),(A2(i)+k22/2),(R1(i)+k23/2));
k41=h*f1((A2(i)+k32));
k42=h*f2((A1(i+1)),(A2(i)+k32),(R1(i)+k33),(R2(i)+k34));
k43=h*f3((R2(i)+k34));
k44=h*f4((A1(i)),(A2(i)+k32),(R1(i)+k33));
A1(i+1) = A1(i) + (k11+2*k21+2*k31+k41)/6;
A2(i+1) = A2(i) + (k12+2*k22+2*k32+k42)/6;
R1(i+1) = R1(i) + (k13+2*k23+2*k33+k43)/6;
R2(i+1) = R2(i) + (k14+2*k24+2*k34+k44)/6;
end
Theta=A1;
r=R1;
subplot(2,2,1)
plot(t,A1,'LineWidth',1)
title('theta vs t')
xlabel('t','fontsize',14,'fontweight','bold')
ylabel('Theta','fontsize',14,'fontweight','bold')
subplot(2,2,2)
plot(t,R1,'LineWidth',1)
xlabel('t','fontsize',14,'fontweight','bold')
ylabel('r','fontsize',14,'fontweight','bold')
subplot(2,2,[3,4])
x=R1.*sin(A1)
y=-R1.*cos(A1)
plot(x,y)
end

댓글 수: 1

Netanel Malihi
Netanel Malihi 2022년 1월 2일
yea it was my mistake i left the code with that mistake but still it's not working.well it's working but the answere in not correct.

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Torsten
Torsten 2022년 1월 2일
편집: Torsten 2022년 1월 2일

1 개 추천

function main
g = 9.81;
m = 71;
k = 1000;
l_0 = 8;
tstart = 0.0;
tend = 10.0;
h = 0.01;
T = (tstart:h:tend).';
Y0 = [pi/6, 0, 10, 0];
f = @(t,y) [y(2), -2*y(4)/y(3)*y(2)-g*sin(y(1)), ...
y(4), y(3)*y(2)^2+g*cos(y(1))-k*(y(3)-l_0)/m];
Y = runge_kutta_RK4(f,T,Y0);
plot(T,Y)
end
function Y = runge_kutta_RK4(f,T,Y0)
N = numel(T);
n = numel(Y0);
Y = zeros(N,n);
Y(1,:) = Y0;
for i = 2:N
t = T(i-1);
y = Y(i-1,:);
h = T(i) - T(i-1);
k0 = f(t,y);
k1 = f(t+0.5*h,y+k0*0.5*h);
k2 = f(t+0.5*h,y+k1*0.5*h);
k3 = f(t+h,y+k2*h);
Y(i,:) = y + h/6*(k0+2*k1+2*k2+k3);
end
end

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