Runge kutta 4 probelm
이전 댓글 표시
What's the problem with this runge kutta code ?
for this parametrs (71,1000,8,10,pi/6,0,0,0.1,10)
function [Theta,r]=test3rk4(m,k,l_0,R1,A1,R2,A2,h,t_end)
t=0:h:t_end;
% A1 = zeros(1,numel(t)) % A2 = A1; R1 = A1; R2 = A1;
% R1 = zeros(1,numel(t))
g=9.81;
f1=@(A2) A2;
f2=@(A1,A2,R1,R2) -2*(R2./R1).*A2-g*sin(A1);
f3=@(R2) R2;
f4=@(A1,A2,R1) R1.*(A2.*A2)+g*cos(A1)-k*(R1-l_0)/m;
for i=1:(length(t)-1)
k11=h*f1(A2(i));
k12=h*f2(A1(i),A2(i),R1(i),R2(i));
k13=h*f3(R2(i));
k14=h*f4(A1(i),A2(i),R1(i));
k21=h*f1((A2(i)+k12/2));
k22=h*f2((A1(i)+k11/2),(A2(i)+k12/2),(R1(i)+k13/2),(R2(i)+k14/2));
k23=h*f3((R2(i)+k14/2));
k24=h*f4((A1(i)+k11/2),(A2(i)+k12/2),(R1(i)+k13/2));
k31=h*f1((A2(i)+k22/2));
k32=h*f2((A1(i)+k21/2),(A2(i)+k22/2),(R1(i)+k23/2),(R2(i)+k24/2));
k33=h*f3((R2(i)+k24/2));
k34=h*f4((A1(i)+k21/2),(A2(i)+k22/2),(R1(i)+k23/2));
k41=h*f1((A2(i)+k32));
k42=h*f2((A1(i+1)),(A2(i)+k32),(R1(i)+k33),(R2(i)+k34));
k43=h*f3((R2(i)+k34));
k44=h*f4((A1(i)),(A2(i)+k32),(R1(i)+k33));
A1(i+1) = A1(i) + (k11+2*k21+2*k31+k41)/6;
A2(i+1) = A2(i) + (k12+2*k22+2*k32+k42)/6;
R1(i+1) = R1(i) + (k13+2*k23+2*k33+k43)/6;
R2(i+1) = R2(i) + (k14+2*k24+2*k34+k44)/6;
end
Theta=A1;
r=R1;
subplot(2,2,1)
plot(t,A1,'LineWidth',1)
title('theta vs t')
xlabel('t','fontsize',14,'fontweight','bold')
ylabel('Theta','fontsize',14,'fontweight','bold')
subplot(2,2,2)
plot(t,R1,'LineWidth',1)
xlabel('t','fontsize',14,'fontweight','bold')
ylabel('r','fontsize',14,'fontweight','bold')
subplot(2,2,[3,4])
x=R1.*sin(A1)
y=-R1.*cos(A1)
plot(x,y)
end
댓글 수: 3
John D'Errico
2022년 1월 2일
When you edit away your question, you are being rude to the person who spent their time answering your question. You make it impossible for others to get help from that same problem. Someone else might be able to learn something. Now your question is useless to others.
If your plan was to do exactly this, then you should never ask the question in the first place.
Rena Berman
2022년 1월 25일
(Answers Dev) Restored edit
James Tursa
2022년 1월 31일
k42 and k44 do not have the correct A1 terms.
답변 (2개)
k42=h*f2((A1(i+1)),(A2(i)+k32),(R1(i)+k33),(R2(i)+k34));
That line requires that A1(i+1) exists before A1(i+1) has been assigned to.
[t,r] = test3rk4(71,1000,8,10,pi/6,0,0,0.1,10)
function [Theta,r]=test3rk4(m,k,l_0,R1,A1,R2,A2,h,t_end)
t=0:h:t_end;
% A1 = zeros(1,numel(t)) % A2 = A1; R1 = A1; R2 = A1;
% R1 = zeros(1,numel(t))
g=9.81;
f1=@(A2) A2;
f2=@(A1,A2,R1,R2) -2*(R2./R1).*A2-g*sin(A1);
f3=@(R2) R2;
f4=@(A1,A2,R1) R1.*(A2.*A2)+g*cos(A1)-k*(R1-l_0)/m;
for i=1:(length(t)-1)
k11=h*f1(A2(i));
k12=h*f2(A1(i),A2(i),R1(i),R2(i));
k13=h*f3(R2(i));
k14=h*f4(A1(i),A2(i),R1(i));
k21=h*f1((A2(i)+k12/2));
k22=h*f2((A1(i)+k11/2),(A2(i)+k12/2),(R1(i)+k13/2),(R2(i)+k14/2));
k23=h*f3((R2(i)+k14/2));
k24=h*f4((A1(i)+k11/2),(A2(i)+k12/2),(R1(i)+k13/2));
k31=h*f1((A2(i)+k22/2));
k32=h*f2((A1(i)+k21/2),(A2(i)+k22/2),(R1(i)+k23/2),(R2(i)+k24/2));
k33=h*f3((R2(i)+k24/2));
k34=h*f4((A1(i)+k21/2),(A2(i)+k22/2),(R1(i)+k23/2));
k41=h*f1((A2(i)+k32));
k42=h*f2((A1(i+1)),(A2(i)+k32),(R1(i)+k33),(R2(i)+k34));
k43=h*f3((R2(i)+k34));
k44=h*f4((A1(i)),(A2(i)+k32),(R1(i)+k33));
A1(i+1) = A1(i) + (k11+2*k21+2*k31+k41)/6;
A2(i+1) = A2(i) + (k12+2*k22+2*k32+k42)/6;
R1(i+1) = R1(i) + (k13+2*k23+2*k33+k43)/6;
R2(i+1) = R2(i) + (k14+2*k24+2*k34+k44)/6;
end
Theta=A1;
r=R1;
subplot(2,2,1)
plot(t,A1,'LineWidth',1)
title('theta vs t')
xlabel('t','fontsize',14,'fontweight','bold')
ylabel('Theta','fontsize',14,'fontweight','bold')
subplot(2,2,2)
plot(t,R1,'LineWidth',1)
xlabel('t','fontsize',14,'fontweight','bold')
ylabel('r','fontsize',14,'fontweight','bold')
subplot(2,2,[3,4])
x=R1.*sin(A1)
y=-R1.*cos(A1)
plot(x,y)
end
function main
g = 9.81;
m = 71;
k = 1000;
l_0 = 8;
tstart = 0.0;
tend = 10.0;
h = 0.01;
T = (tstart:h:tend).';
Y0 = [pi/6, 0, 10, 0];
f = @(t,y) [y(2), -2*y(4)/y(3)*y(2)-g*sin(y(1)), ...
y(4), y(3)*y(2)^2+g*cos(y(1))-k*(y(3)-l_0)/m];
Y = runge_kutta_RK4(f,T,Y0);
plot(T,Y)
end
function Y = runge_kutta_RK4(f,T,Y0)
N = numel(T);
n = numel(Y0);
Y = zeros(N,n);
Y(1,:) = Y0;
for i = 2:N
t = T(i-1);
y = Y(i-1,:);
h = T(i) - T(i-1);
k0 = f(t,y);
k1 = f(t+0.5*h,y+k0*0.5*h);
k2 = f(t+0.5*h,y+k1*0.5*h);
k3 = f(t+h,y+k2*h);
Y(i,:) = y + h/6*(k0+2*k1+2*k2+k3);
end
end
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