Hi guys,
How would I write a for loop in which the loop variable runs from 0 to pi/2 in steps of 0.01?
Am i right in saying:
for
A = 0:0.01:pi/2
end
Is this correct?

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Yusuf Suer Erdem
Yusuf Suer Erdem 2021년 12월 7일
편집: Yusuf Suer Erdem 2021년 12월 7일

2 개 추천

for a=0:a+0.01:pi/2
disp(a)
end

댓글 수: 4

Laura T
Laura T 2021년 12월 7일
Thank you! And if i were to add inside this loop do i need to disp(i) every time i enter a new line of code?
Yusuf Suer Erdem
Yusuf Suer Erdem 2021년 12월 7일
disp(i) is just to show you that the loop works. you could do anything you want with that i value.
The colon operation given in the answer uses the imaginary unit in the step, which leads to this warning:
0:i+0.01:pi/2
Warning: Colon operands must be real scalars.
ans = 1×158
0 0.0100 0.0200 0.0300 0.0400 0.0500 0.0600 0.0700 0.0800 0.0900 0.1000 0.1100 0.1200 0.1300 0.1400 0.1500 0.1600 0.1700 0.1800 0.1900 0.2000 0.2100 0.2200 0.2300 0.2400 0.2500 0.2600 0.2700 0.2800 0.2900
I don't see any reason why the step needs to use the imaginary unit.
Yusuf Suer Erdem
Yusuf Suer Erdem 2021년 12월 7일
maybe used i as a character. i changed it with a. it should be okey now.

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