Hello,
I am trying to use xlim to limit my x-axis
h_to_plot = linspace(1,20,20);
horizon = 1:1:20;
quant = 1.64;
mat = [coefficients ses [1:1:20]'];
[~,idx] = sort(mat(:,1));
sortedmat = mat(idx,:);
figure(3)
errorbar(horizon(h_to_plot),sortedmat(h_to_plot,1),quant*sortedmat(h_to_plot,2),'o','Linewidth',2)
hold on
xlim = ([0 20.5])
However, I could not make x-axis starts from 0 to 20.5
Is there any way I could use xlim to extend my x axis to 20.5?
Thanks

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VBBV
VBBV 2021년 12월 3일

0 개 추천

xlim([0 20.5]) % difference
Difference in using and = between the xlim and parenthesis

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Ajay S
Ajay S 2022년 12월 26일
bruh can you please make it a bit more clear
Simon
Simon 2025년 2월 12일
xlim([0 20.5]) is correct
xlim = ([0 20.5]) is incorrect
The command:
xlim = ([0 20.5])
xlim = 1×2
0 20.5000
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
creates a variable named xlim. While that variable exists, attempts to call the xlim function in that context will instead be interpreted as an attempt to index into that variable. For example, if I try to then set the limits to the vector [-1 1] using the xlim function, MATLAB will throw an error since there's no such thing as the -1st element of an array in MATLAB:
xlim([-1 1])
Array indices must be positive integers or logical values.

xlim appears to be both a function and a variable. If this is unintentional, use 'clear xlim' to remove the variable 'xlim' from the workspace.
Paul
Paul 2025년 2월 12일
I don't think I've ever seen this error message before idenitfying the ambiguity between the variable and the function. Is that new?
Is there any overhead incurred by Matlab having to determine the xlim is also a function in this case?
Would it also indicate if xlim is some other useful thing, like an .m file or .slx file or a class definition?
DGM
DGM 2025년 2월 13일
This is a common mistake, and future readers should make sure that the variable that they mistakenly created gets cleared, otherwise the error will persist even after the code is fixed.
clear xlim

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