# Distribute a sum using binomial distribution

조회 수: 5(최근 30일)
Vorticella aequilata 2021년 12월 2일
편집: David Goodmanson 2021년 12월 2일
I have a matrix say 'a' (3x6). According to the binomial distribution, I want to divide the sum of each row into a new matrix with two collumns (e.g. 'distribute1'). For this I use binornd but i want the values of the numbers generated to sum up to the value of the sum of each row. For example, let's say a row sums up to 5. The values generated by binornd should be either: 0 and 5, 1 and 4 or 2 and 3.
Is it correct to use binornd? Should I use binopdf?
If it helps, I am trying to make a script from a paper. This is wat it says: "the total RNAs in them [in my case it is equal to the sum of each row of 'a'] were distributed into two compartments [in my case 'distribute1,2 or 3'] according to the binomial distribution" 10.1038/s41559-018-0650-z
What is the logic for chosing the values of the n (no of trials) and p (probability of succes in each trial) input arguments? For now, I used the row sum as n and 0.5 as p. But I'm not sure if it is correct (these parameters are not mentioned in the paper).
Here is my code:
a=[1 2 3 4 5 6; 7 8 9 10 11 12; 13 14 15 16 17 18]
suma=sum(a,2)
distribute1=binornd(suma(1,:),0.5,[1 2])
distribute2=binornd(suma(2,:),0.5,[1 2])
distribute3=binornd(suma(3,:),0.5,[1 2])
Than you!

댓글을 달려면 로그인하십시오.

### 채택된 답변

David Goodmanson 2021년 12월 2일
편집: David Goodmanson 2021년 12월 2일
Hi Vorticella,
In the code you are using, the two numbers are chosen independently and usually don't add up to be the row sum. if a given row sums up to n, then I believe the required result is
a = binornd(n,.5,1)
result = [a n-a]
Here binornd picks the number of times the left column is chosen, and the remainder are put into the right column. You still have to decide on the probability p, and in the absence of any other information, p = .5 is more or less implied.

댓글을 달려면 로그인하십시오.

### 추가 답변(1개)

Jeff Miller 2021년 12월 2일
If I understand correctly,
• it is fine to use binornd with n = row total. It sounds like that is what was done in the paper.
• just use binornd to get the number in the first compartment for each row; the number in the second compartment is the row n minus the number in the first compartment.
• it makes sense to use p = 0.5 if you expect both compartments to get the same number in the long run. If that doesn't make sense in your situation, you might make p higher/lower to get more/less in the first compartment.
Hope that helps

댓글을 달려면 로그인하십시오.

### Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by