Save mean values in additional column

조회 수: 1 (최근 30일)
Daeyeon Koh
Daeyeon Koh 2021년 11월 27일
답변: DGM 2021년 11월 27일
j=1;
for i=1:rowC
if Allpeaks(i,2)>4.33&&Allpeaks(i,2)<5.13
Range1peaks(j,:)=Allpeaks(i,:);
j=j+1;
end
end
[aaaaa_DummyIdx,Peaks_index1]=sort(Range1peaks(:,3));
Arg_Range1peaks=Range1peaks(Peaks_index1(1:1:end,:),:);
Sputum_Idx(:,1) = unique(Arg_Range1peaks(:,3));
for i = 1:numel(Sputum_Idx(:,1))
ind=(Arg_Range1peaks(:,3)==Sputum_Idx(i,1));
MeanV1(i,1) = mean(Arg_Range1peaks(ind));
end
Mean1 = [MeanV1 Sputum_Idx(:,1)];
Hello. After obtaining the N x 3 vector as shown in the picture above ([Range1 peaks]), I listed it in order of size in columns 3 through indexing ([Arg_Range1 peaks]).
In addition, the average values of column 1 values([Arg_Range1 peaks]) were saved for rows with the same values in column 3 ([Mean1]).
As shown in the rightmost figure, we would like to place mean values of [Mean1] corresponding to column 3 in column 4 of [Arg_Range1 peaks]. What should I do?

채택된 답변

DGM
DGM 2021년 11월 27일
Something like this
% dummy data
N = 15;
Range1peaks = [10*rand(N,1)-70 2*rand(N,1)+4 randi([0 5],N,1)]
Range1peaks = 15×3
-64.2527 5.7079 1.0000 -61.6632 5.7425 3.0000 -67.5955 5.6379 4.0000 -60.7405 5.1714 1.0000 -66.4285 5.7260 3.0000 -60.1289 5.2518 2.0000 -64.3149 5.8483 4.0000 -69.3145 4.4015 4.0000 -66.4578 4.5760 5.0000 -69.5323 4.9063 3.0000
% sort
[~,Peaks_index1] = sort(Range1peaks(:,3),1,'ascend');
Arg_Range1peaks = Range1peaks(Peaks_index1,:);
% append column, take mean, fill
Arg_Range1peaks = [Arg_Range1peaks zeros(size(Arg_Range1peaks,1),1)];
Sputum_Idx = unique(Arg_Range1peaks(:,3));
for i = 1:numel(Sputum_Idx)
ind=(Arg_Range1peaks(:,3)==Sputum_Idx(i));
Arg_Range1peaks(ind,4) = mean(Arg_Range1peaks(ind,1));
end
% show result
Arg_Range1peaks
Arg_Range1peaks = 15×4
-65.2151 5.6245 0 -66.5816 -67.9481 4.8178 0 -66.5816 -64.2527 5.7079 1.0000 -64.6457 -60.7405 5.1714 1.0000 -64.6457 -65.2107 5.4760 1.0000 -64.6457 -68.3787 4.5315 1.0000 -64.6457 -60.1289 5.2518 2.0000 -60.1289 -61.6632 5.7425 3.0000 -65.8747 -66.4285 5.7260 3.0000 -65.8747 -69.5323 4.9063 3.0000 -65.8747

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Descriptive Statistics에 대해 자세히 알아보기

제품


릴리스

R2019b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by