A =[ -4.7107
0.0012
-0.0056
0.0132
-0.0253
0.0435
-0.0689
0.1031
-0.1473
0.2040
-0.2737
0.3607
-0.4647
0.5927
-0.7425
0.9265
-1.1387
1.4014
-1.7014
2.0810
-2.5114
3.0805
-3.7224
4.6475
-5.6872
7.5039
-9.5388
16.4146
-25.4535
14.3236];
B=[ -3.3794
0.0005
-0.0009
0.0006
-0.0003
0.0001
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000];
C=[ 6.8417
-0.0007
0.0007
-0.0003
0.0001
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000];
D=[ -4.7100
-0.0012
0.0058
-0.0132
0.0253
-0.0435
0.0689
-0.1032
0.1473
-0.2040
0.2737
-0.3608
0.4648
-0.5928
0.7426
-0.9266
1.1388
-1.4016
1.7016
-2.0813
2.5118
-3.0810
3.7230
-4.6482
5.6881
-7.5050
9.5403
-16.4171
25.4574
-14.3258];
E=[ -3.3789
-0.0005
0.0009
-0.0006
0.0003
-0.0001
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000];
F=[ 6.8407
0.0007
-0.0008
0.0003
-0.0001
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000];
a = 1 ; %RADIUS
L=.1;
dd=4;
kappa=1;gam=0.3;arh=1; %a2=1;u2=1;beta1=beta2=1
al=kappa.*(2+kappa)./(gam.*(1+kappa));
alpha1=real(((al.^2+arh.^2)./2+((al.^2+arh.^2).^2-(2.*kappa.*arh.^2./gam).^(1./2))./2).^(1./2));
alpha2=real(((al.^2+arh.^2)./2-((al.^2+arh.^2).^2-(2.*kappa.*arh.^2./gam).^(1./2))./2).^(1./2));
c =-a/L;
b =a/L;
m =a*100; % NUMBER OF INTERVALS
[x,y]=meshgrid([c+dd:(b-c)/m:b],[c:(b-c)/m:b]);
[I, J]=find(sqrt(x.^2+y.^2)<(a-.1));
if ~isempty(I)
x(I,J) = 0; y(I,J) = 0;
end
r=sqrt(x.^2+y.^2);
t=atan2(y,x);
r2=sqrt(r.^2+dd.^2-2.*r.*dd.*cos(t));
zet=(r.^2-r2.^2-dd.^2)./(2.*r2.*dd);
%for i1=1:length(x);
% for k1=1:length(x);
% if sqrt(x(i1,k1).^2+y(i1,k1).^2)>1./L;
% r(i1,k1)=0;r2(i1,k1)=0;
% end
% end
%end
warning off
qr1=0;
for i=2:7
Ai=A(i-1);Bi=B(i-1);Ci=C(i-1);Di=D(i-1);Ei=E(i-1);Fi=F(i-1);
qr1=qr1-(Ai.*r.^(-i-1)+r.^(-3./2).*besselk(i-1./2,r.*alpha1).*Bi+r.^(-3./2).*besselk(i-1./2,r.*alpha2).*Ci).*legendreP(i-1,cos(t))-(Di.*r2.^(-i-1)+r2.^(-3./2).*besselk(i-1./2,r2.*alpha1).*Ei+r2.^(-3./2).*besselk(i-1./2,r2.*alpha2).*Fi).*legendreP(i-1,zet);
end
hold on
[DH1,h1]=contour(x,y,qr1,3,'-k');
%axis square;
title('$(a)$ $\ell=0.1,\;\alpha=1.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')
%%%%%%%%%%%%%%%% $\frac{\textstyle a_1+a_2}{\textstyle h}=6.0,\;
hold on
t3 = linspace(0,2*pi,1000);
h2=0;
k2=0;
rr2=1;
x2 = rr2*cos(t3)+h2;
y2 = rr2*sin(t3)+k2;
set(plot(x2,y2,'-k'),'LineWidth',1.1);
fill(x2,y2,'w')
%axis square;
hold on
t2 = linspace(0,2*pi,1000);
h=dd;
k=0;
rr=2;
x1 = rr*cos(t2)+h;
y1 = rr*sin(t2)+k;
set(plot(x1,y1,'-k'),'LineWidth',1.1);
fill(x1,y1,'w')
%axis square;
axis off

댓글 수: 1

Adam Danz
Adam Danz 2021년 11월 20일
Shreen El-Sapa's answer moved here
I can not get the streamlines

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 채택된 답변

Cris LaPierre
Cris LaPierre 2021년 11월 20일

1 개 추천

qr1 is all NaNs. Assuming the countours are supposed to be your streamlines, you should check your equation. I'm not sure your for loop is doing what you intended. At the least, there is an issue with your calculation.

댓글 수: 5

Shreen El-Sapa
Shreen El-Sapa 2021년 11월 20일
편집: Cris LaPierre 2021년 11월 20일
edited code to make it more readable
A=[-4.7107 0.0012 -0.0056 0.0132 -0.0253 0.0435 -0.0689 0.1031 -0.1473 0.2040 -0.2737 0.3607 -0.4647 0.5927 -0.7425 0.9265 -1.1387 1.4014 -1.7014 2.0810 -2.5114 3.0805 -3.7224 4.6475 -5.6872 7.5039 -9.5388 16.4146 -25.4535 14.3236];
B=[-3.3794 0.0005 -0.0009 0.0006 -0.0003 0.0001 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0];
C=[6.8417 -0.0007 0.0007 -0.0003 0.0001 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0];
AA=[-4.7100 -0.0012 0.0058 -0.0132 0.0253 -0.0435 0.0689 -0.1032 0.1473 -0.2040 0.2737 -0.3608 0.4648 -0.5928 0.7426 -0.9266 1.1388 -1.4016 1.7016 -2.0813 2.5118 -3.0810 3.7230 -4.6482 5.6881 -7.5050 9.5403 -16.4171 25.4574 -14.3258];
BB=[-3.3789 -0.0005 0.0009 -0.0006 0.0003 -0.0001 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0];
CC=[6.8407 0.0007 -0.0008 0.0003 -0.0001 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0];
a = 1 ; %RADIUS
L=.13;
akm=1;gamma=0.3;arh=0.1;
alphaa=sqrt(((2+akm).*(akm./gamma)).^2+arh.^2);
betaa=(2.*akm.*arh.^2./gamma).^(0.25);
alpha1=sqrt((alphaa.^2+sqrt(alphaa.^4-4.*betaa.^4))./2);
alpha2=sqrt((alphaa.^2-sqrt(alphaa.^4-4.*betaa.^4))./2);
dd=5;
c =-a/L;
b =a/L;
m =a*50; % NUMBER OF INTERVALS
[x,y]=meshgrid([c+dd:(b-c)/m:b],[c:(b-c)/m:b]');
[I J]=find(sqrt(x.^2+y.^2)<(a-.1));
if ~isempty(I);
x(I,J) = 0; y(I,J) = 0;
end
r=sqrt(x.^2+y.^2);
t=atan2(y,x);
r2=sqrt(r.^2+dd.^2-2.*r.*dd.*cos(t));
zet=(r.^2-r2.^2-dd.^2)./(2.*r2.*dd);
warning on
psi1=0;
for i=2:3;
Ai=A(i-1);
Bi=B(i-1);
Ci=C(i-1);
AAi=AA(i-1);
BBi=BB(i-1);
CCi=C(i-1);
psi1=-psi1-(Ai.*r.^(-i-1)+r.^(-3./2).*besselk(i-1./2,r.*alpha1).*Bi+r.^(-3./2).*besselk(i-1./2,r.*alpha2).*Ci).*legendreP(i-1,cos(t))-(AAi.*r2.^(-i-1)+r2.^(-3./2).*besselk(i-1./2,r2.*alpha1).*BBi+r2.^(1./2).*besselk(i-1./2,r2.*alpha2).*CCi).*legendreP(i-1,zet);
end
[DH1,h1]=contour(x,y,psi1,20,'-k');
title('$(a)$ $\ell=0.1,\;\alpha=1.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')
hold on
t3 = linspace(0,2*pi,1000);
h2=0;
k2=0;
rr2=1;
x2 = rr2*cos(t3)+h2;
y2 = rr2*sin(t3)+k2;
set(plot(x2,y2,'-k'),'LineWidth',1.1);
fill(x2,y2,'w')
t2 = linspace(0,2*pi,1000);
h=dd;
k=0;
rr=2;
x1 = rr*cos(t2)+h;
y1 = rr*sin(t2)+k;
set(plot(x1,y1,'-k'),'LineWidth',1.1);
fill(x1,y1,'w')
axis off
hold off
Cris LaPierre
Cris LaPierre 2021년 11월 20일
Ok. Is this what you wanted? If not, you're going to have to describe better what it is you expect.
Shreen El-Sapa
Shreen El-Sapa 2021년 11월 20일
But this program plots streamlines directly without determining what is each value of streamlines over the contour? can you help me or anyone?
thanks
Cris LaPierre
Cris LaPierre 2021년 11월 20일
Personally, I use the streamlines function to create streamlines, not contour. However, even with streamlines, you will need to calculate and input the vector field components u and v.
Shreen El-Sapa
Shreen El-Sapa 2021년 11월 20일
I used the equations below. Can I used it to plot the streamlines? as you say?

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