how to create rectangle filter with following condition;
f(t)= 1; -0.1secs< t < 0.1 secs
f(t)= 0; otherwise
Below i have tried but getting error.
n=2048; %samples
fs=1024; %sampling frequency
T=1/fs;
t = (0:n-1)*T;
F=zeros(length(t));
for i=0:length(t)
if t(i)<=0.1
F(i)=1;
else
F(i)=0;
end
end
Array indices must be positive integers or logical values.

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Dave B
Dave B 2021년 11월 20일
편집: Dave B 2021년 11월 20일
In MATLAB indices start with 1:
n=2048; %samples
fs=1024; %sampling frequency
T=1/fs;
t = (0:n-1)*T;
F=zeros(length(t));
for i=1:length(t)
if abs(t(i))<=0.1 % technically better because it covers the negative case
F(i)=1;
else
F(i)=0; % not really needed because you initialized F with all zeros...
end
end
But note, you don't need a loop for this kind of thing:
F2=zeros(length(t));
F2(abs(t)<=.1)=1;
isequal(F2,F)
ans = logical
1

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