how can i quantize the normal distribution using uniform PCM?

sinusoidal signal, there is quantization code for 8 levels and 16 levels using PCM scheme. However, I want to do this for N(0,1) distribution as well. Do I just need to make changes in the "a" variable in this code?

echo on
t=[0:0.01:10];
a=sin(t);
[sqnr8,aquan8,code8]=u_pcm(a,8);
[sqnr16,aquan16,code16]=u_pcm(a, 16);
pause % Press a key to see the SQNR for N = 8.
sqnr8
pause % Press a key to see the SQNR for N = 16.
sqnr16
pause % Press a key to see the plot of the signal and its quantized versions.
plot(t,a,' -',t,aquan8,' - . ',t,aquan16,' -',t,zeros(1,length(t)))

function [sqnr,a_quan,code]=u_pcm(a,n)
%U_PCM  	uniform PCM encoding of a sequence
%       	[SQNR,A_QUAN,CODE]=U_PCM(A,N)
%       	a=input sequence.
%       	n=number of quantization levels (even).
%       	sqnr=output SQNR (in dB).
%		a_quan=quantized output before encoding.
%		code=the encoded output.

amax=max(abs(a));
a_quan=a/amax;
b_quan=a_quan;
d=2/n;
q=d.*[0:n-1];
q=q-((n-1)/2)*d;
for i=1:n
  a_quan(find((q(i)-d/2 <= a_quan) & (a_quan <= q(i)+d/2)))=...
  q(i).*ones(1,length(find((q(i)-d/2 <= a_quan) & (a_quan <= q(i)+d/2))));
  b_quan(find( a_quan==q(i) ))=(i-1).*ones(1,length(find( a_quan==q(i) )));
end
a_quan=a_quan*amax;
nu=ceil(log2(n));
code=zeros(length(a),nu);
for i=1:length(a)
  for j=nu:-1:0
    if ( fix(b_quan(i)/(2^j)) == 1)
	code(i,(nu-j)) = 1;
	b_quan(i) = b_quan(i) - 2^j;
    end
  end
end
sqnr=20*log10(norm(a)/norm(a-a_quan));

Answer 1

[Raikantwar Hrashikesh]

idk