how can i get a horzenital vector?
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X = [2 1 5 1
5 4 8 1
1 4 5 7];
if i use X1 = X(:);
the output is X1=[2
5
1
1
4
4
5
8
5
1
1
7]
but i wante the out put is X1 =[2 1 5 1 5 4 8 1 1 4 5 7];
thank you very much
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채택된 답변
Andrei Bobrov
2011년 9월 14일
X1 = reshape(X',1,[])
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Jan
2011년 9월 14일
@Fangjun: Without the transpose, you get X1 = [2,5,1,...], but Amal wants [2,1,5,...] - the data in row order.
추가 답변 (2개)
Daniel Shub
2011년 9월 14일
If there is any chance that you matrix will have complex numbers you need to be careful with the difference between ' (ctranspose) and .' (transpose). To be clear I might go with:
X1 = transpose(X(:));
I do not know if there is a performance difference between ctranspose and transpose for real matrices.
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Sean de Wolski
2011년 9월 14일
There is not. Though there was a bug with ctranspose in the original release of R2009b.
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