필터 지우기
필터 지우기

symbolic equation solving a a Unknown variable

조회 수: 1 (최근 30일)
Thayumanavan
Thayumanavan 2014년 10월 12일
Te=0.528104000000000;wr=0.955; Pmpu=Te*wr;
Pmactual=Pmpu*5*1000000;
Beta=0.0; gb=121.2; speedact=wr*1500; omegarm=(2*pi*speedact)/(60); wtradsec=omegarm/gb;
c1=0.5176; c2=116; c3=0.4; c4=0; c5=c4; c6=5; c7=21; c8=0.08; c9=0.035; c10=0.0068; syms Vw ; R=40.05; Lamda=(wtradsec*R)/Vw
t1=c2/(Lamda+(c8*Beta)); t2=(c2*c9)/((Beta^3)+1); t3=c3*Beta; t4=c4*(Beta^c5); t5=c6; t6=-c7/(Lamda+(c8*Beta)); t7=(c7*c9)/((Beta^3)+1); t8=c10*Lamda;
cp=(c1*(t1-t2-t3-t4-t5)*exp(t6+t7)) +t8
term=(Pmactual)-(0.5*pi*1.225*(R^2)*cp*Vw*Vw*Vw) symvar(term) Vw=solve(term)
I am getting some answer 49.231911904587234477083430935504 .But is is not correct(anyway i cheked term value is zer0) I tried the exact reverse
With Known Vw
Vw=9.55
Lamda=(wtradsec*R)/Vw t1=c2/(Lamda+(c8*Beta)); t2=(c2*c9)/((Beta^3)+1); t3=c3*Beta; t4=c4*(Beta^c5); t5=c6; t6=-c7/(Lamda+(c8*Beta)); t7=(c7*c9)/((Beta^3)+1); t8=c10*Lamda;
cp=(c1*(t1-t2-t3-t4-t5)*exp(t6+t7)) +t8
term =5415302213717197/2147483648 - Vw^3*((6787202843659081*exp(147/200 - (22624*Vw)/(16999*pi))*((121284032*Vw)/(31873125*pi) - 293091/62500))/2199023255552 + (5884158718107396613869*pi)/(17768107904860160000*Vw)) Pmactual=term+(0.5*pi*1.225*(R^2)*cp*Vw*Vw*Vw) Pmpu=Pmactual/(5*1000000) Te=Pmpu/wr
I am getting same Te as my input.
1.My doubt is why symbolic sove does not gives 9.55 .What mistake i am doing?pls anybody run the code and tell me.
2. While symbol solve MATLAB solves the for Vw for which term is 0 .But in reverse process(ie with Vw known)IF I PRINT TERM it is NON ZER0 why?

답변 (0개)

카테고리

Help CenterFile Exchange에서 Linear Algebra에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by