replacing numbers with alphabets/letters in a matrix
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I have a excel sheet (attached file) consiting of 4000 numbers (1 to 4000). I want to replace 1, 5, 9 ...3997 and 2, 6, 10...3998 with C and 3, 7, 11...3999 and 4,8, 12...4000 with H. Can a code be devised where this task can be performed such that the output file/data is represented in the same array/format as the given input? And can the code be made universal so that we can carry forth similar tasks with other arrays?
Looking forward for an answer and thank you for all your help.
Regards
J
채택된 답변
Akira Agata
2021년 11월 8일
One possible straight-forward solution would be like this:
M = readmatrix('testfile_0.50.xlsx');
C = cell(size(M));
idx = ismember(M,[1:4:3997, 2:4:3998]);
C(idx) = {'C'};
idx = ismember(M,[3:4:3999, 4:4:4000]);
C(idx) = {'H'};
writecell(C,'output.xlsx');
추가 답변 (1개)
Walter Roberson
2021년 11월 8일
편집: Walter Roberson
2021년 11월 8일
filename = 'https://www.mathworks.com/matlabcentral/answers/uploaded_files/793759/testfile_0.50.xlsx';
outfile = "testout.xlsx";
data = readmatrix(filename);
newdata = cell(size(data));
mask = isnan(data);
newdata(mask) = {nan};
mask = ismember(mod(data,4), [1 2]);
newdata(mask) = {'C'};
mask = ismember(mod(data,4), [3 0]);
newdata(mask) = {'H'};
writecell(newdata, outfile);
%testing to see if the output looks ok
readback = readtable(outfile);
readback(10:20,:)
I tested on my system, and excel does show those 0x0 char and NaN entries as empty cells.
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