simple Fixed Point Iteration
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clear all;
clc;
x(1)=0;
g=@(x) exp(-x);
f=@(x) exp(-x)-x;
true_root=0.56714329;
disp('----------------------------------------------------');
disp('i xi Ea(%) Et(%) ');
disp('----------------------------------------------------');
for i=1:10
x(i+1)=g(x(i));
end
if x~=0
ea=100*abs(x(i+1)-g(x(i))/x(i+1));
end
e_t=100*abs(x-true_root)/true_root;
res=[[0:10]' x' ea' e_t'];
fprintf('%d %1.6f %3.3f %3.3f\n', res');
i want to add the ea. but i can. how can i this??
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Alan Stevens
2021년 11월 7일
Probably more like this (though you don't seem to have used function f anywhere):
n = 11;
x = zeros(1,numel(n));
ea = zeros(1,numel(n));
g=@(x) exp(-x);
f=@(x) exp(-x)-x;
true_root=0.56714329;
disp('----------------------------------------');
disp('i xi Ea(%) Et(%) ');
disp('----------------------------------------');
for i=1:n-1
x(i+1)=g(x(i));
if x(i+1)~= 0
ea(i+1) = 100*abs(x(i+1)-x(i))/x(i+1);
end
end
e_t = 100*abs(x-true_root)/true_root;
res=[(0:n-1)' x' ea' e_t'];
fprintf('%d %10.6f %10.3f %10.3f\n', res');
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