search and replace exact substring
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Hello,
I am parsing a string to check for an exact phrase. If the exact phrase is found, then I want to replace the phrase with a new phrase. The problem is, sometimes the phrase will be part of anothe phrase. Example:
wish to change the phrase "eps" to "%eps"
str = 'steps = eps*100 + beta*steps*eps';
newStr = 'steps = %eps*100 + beta*steps*%eps';
I'm having trouble picking out the exact phrase; each parsing phrase that I've come up with always catches something undesired e.g. 'steps' => 'st%eps' etc.
I've tried things like: st1 = regexprep(str,'^\w*(?=eps)^\w*','%eps')
(where I think I'm saing, look around the phrase "eps", if there's no "word" in the regexp sense, then replace the phrase with "%eps", but I'm obviously not there yet.
TIA,
CDQ (R2011b)
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Azzi Abdelmalek
2014년 10월 8일
편집: Azzi Abdelmalek
2014년 10월 8일
str = 'steps = eps*100 + beta*steps*eps';
regexprep([' ' str ' '],'(?<=[^a-zA-Z])eps(?=[^a-zA-Z])','%eps')
추가 답변 (1개)
Image Analyst
2014년 10월 8일
newString = strrep(oldString, ' eps', ' %eps');
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Image Analyst
2014년 10월 9일
You could do it in two lines of code instead of one:
newString = strrep(oldString, ' eps', ' %eps');
newString = strrep(newString, '*eps', '%eps');
Likewise in the event you have any other symbols. Sorry for not doing this in the first place - thought you'd know. I find this much easier, and more straightforward and intuitive than trying to compose/invent complicated regexp expressions, so that's why I suggested it. Looks like you're quite adept with regexp though and can understand things like ' (?<=[^a-zA-Z])eps(?=[^a-zA-Z]) ', and that's great, because not everybody can.
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