I'm adding a constraint to my problem, the two constraints are the ones inside c. I want my c output to be 46 x 4 = 184 values. However, when i run my code, as the two “for loops” are completed, the value of “c” is replaced. In other words, the old value of “c” is forgotten when the loop takes different values of “i” and “h” and only the last value of “c” for h=23 and i=4 are returned to the main routine. what can i do to solve this?
for h= 1:23
for i =1:4
c = [-DR(i)-p(h+1,i)+p(h,i);p(h+1,i)-p(h,i)-UR(i)];
end
end

답변 (1개)

Stephen23
Stephen23 2021년 10월 28일
편집: Stephen23 2021년 10월 28일

1 개 추천

"what can i do to solve this?"
Use indexing into a preallocated array:
c = nan(46,4); % <--- preallocate!
for h = 1:23
for i = 1:4
c(2*h-[1,0],i) = [-DR(i)-p(h+1,i)+p(h,i);p(h+1,i)-p(h,i)-UR(i)];
end % ^^^^^^^^^^^ indexing!
end
Given the simplicity of those constraint calculations, it is possible that loops are not required: have you looked at vectorizing your code?

카테고리

도움말 센터File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

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질문:

2021년 10월 28일

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2021년 10월 28일

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