why do i recive Index in position 2 is invalid. Array indices must be positive integers or logical values

Hi every one

i have tried to implement for loop in order to compute the model the idea is how can i compute this model at the first iteration then i have to compute it again in the folloing iteration

u=[p;s;c] this is the u column vector of my model with 153*1 dimension where p,s,c 51*1

iteration =10;

iteration(:,1)=u(:) here i would like to say that at first iteration compute the model from p,s,c inputs but i have got the error meassage as titled in the question so how can i do that

this is what iam trying to do

for i =1:iteration

[unkown, unknown,unknown ]=function([u(1),u(2),u(3)])

iteration(:,i+1)=u(:) here i want to increase the iteration counter

end

so how can i do

thank you

[hamza karim]

I coudn't really understand your question but your code is quite odd.

first you are defining iteration as a scalar. Then by writing

iteration(:,1)=u(:)

you are simply overwritting your initial value of 10, here you would have iteration as a vector of size 153x1 as per your u vector.

then when you are writing your for loop, you say

for i=1:iteration

end

this does not make sense. If your objective is to make 10 iteration you simply write

for i=1:10

end

and if the iteration is as per your u vector size then

for i=1:length(u)

end

as your code is written

at the ligne

iteration(:,i+1)=u(:)

is as you are saying iteration(:,2)=u(:) which is impossible since iteration is initially a vector of size 153x1

Answer 1

[Cris LaPierre]

This error means that you are not using integer values to index your array. Position 2 indicates it is your column index that is incorrect.

A=rand(2);
% works
A(1,2)

ans = 0.2686

% doesn't work
A(1,1.5)

Index in position 2 is invalid. Array indices must be positive integers or logical values.