How to covert a 1D vector to 2D matrix with overlapping effectively?

Dear Experts,

I would like to make a function to covert a 1D vector to a 2D matrix form with overlapping.

==

X = [1, 2, 3, 4, 5 , 6, 7, 8, 9, 10, 11, 12, 13, 14, 15]

segment_size = 4; overlap_rate = 0.5

== Expected Results ===

[ 1 3 5 ... 12

2 4 6 ... 13

3 5 7 ... 14

4 6 8 ... 15]

It would be good to use some functions instead of using "for loop".

Thank you

Answer 1

[Matt J]

X=randi(30, 1,14);

segment_size = 4; 
overlap_rate = 0.5;
d=segment_size*overlap_rate;

idx=(1:segment_size)'+ ( 0:d:(numel(X)-segment_size) );
[~,rec]=unique(idx); 
rec=rec(:).';

X,

X = 1×14

9 13 10 9 4 30 12 28 27 20 18 20 12 18

Matrix=X(idx)

Matrix = 4×6

9 10 4 12 27 18 13 9 30 28 20 20 10 4 12 27 18 12 9 30 28 20 20 18

Xrec=Matrix(rec)

Xrec = 1×14

9 13 10 9 4 30 12 28 27 20 18 20 12 18

[Kim]

Thank you for your prompt reply.

I just have quick a question. Then, can you please let me know how to return the 2-D matrix back to a 1-D vector?

[Matt J]

Thank you for your prompt reply.

You're welcome, but please Accept-click the answer if it fulfills your question.

Then, can you please let me know how to return the 2-D matrix back to a 1-D vector?

I will add it to my Answer.

[Kim]

Thanks a million!