Converting a binary matrix to decimal.

I change the 3-bit binary matrix(a, e) to decimal -> change the decimal to a 4-bit binary matrix -> Add changed a and e = A

The following errors occur.

bin2dec :

The input argument must be a cell type array consisting of a character type vector, string type, or character type vector.

What is the way to correct the error?

Below is the code content.

function A = Xasum(X)

N = 64;

for k = 1 : N

x = X(k, :);

a = x(:, [1,2,3]);

e = x(:, [4,5,6]);

bin2dec(a);

dec2bin((a),4);

bin2dec(e);

dec2bin((e),4);

A = (a + e)';

end

end

X = [0 0 0 0 0 0;

0 0 0 0 0 1;

0 0 0 0 1 0;

0 0 0 0 1 1;

0 0 0 1 0 0;

0 0 0 1 0 1;

0 0 0 1 1 0;

0 0 0 1 1 1;

0 0 1 0 0 0;

0 0 1 0 0 1;

0 0 1 0 1 0;

0 0 1 0 1 1;

0 0 1 1 0 0;

0 0 1 1 0 1;

0 0 1 1 1 0;

0 0 1 1 1 1;

...

...

...

1 1 1 1 0 1;

1 1 1 1 1 0;

1 1 1 1 1 1;

];

Answer 1

[Jan]

The error message is clear: bin2dec requires a CHAR vector as input or a cell string. See:

doc bin2dec

You provide a numerical vector consisting on 1s and 0s.

This part of the code does not assigbn the results to a varible, so the computations are lost and only a waste of time:

    bin2dec(a);
    dec2bin((a),4);
    bin2dec(e);
    dec2bin((e),4);    

What do you want to achieve? a and e are not changed here.

The result A is overwritten in each iteration:

    A = (a + e)';

At the end, A contains the value of the last iteration k=N only. Is this wanted?

What is the wanted output for:

X = [0 0 0 0 0 0; ...
     0 0 0 0 0 1; ...
     0 0 0 0 1 0];

[level1]

Divide the input 6 bits into 3 bits. After that, add two three bits. I want to print that value in 4 bits.

I'm trying this and that because I'm not good at matlab.

The biggest problem is to divide 6 bits into 3 bits and output the added value to 4 bits.

[Jan]

Again: What is the wanted output for the given X?

Splitting the array is easy:

X = [0 0 0 0 0 0; ...
     0 0 0 0 0 1; ...
     0 0 0 0 1 0];
X1 = X(:, 1:3)
X2 = X(:, 4:6)

Expanding this to 4 bits means inserting columns with zeros:

nRow = size(X, 1);
Y = [zeros(nRow, 1), X1, zeros(nrow, 1), X2];

[level1]

sorry.I didn't know you were asking me to explain the result in code.

D = [0 0 0 0;

0 0 0 1;

0 0 1 0;

0 0 1 1;

0 1 0 0;

0 1 0 1;

0 1 1 0;

0 1 1 1;

1 0 0 0;

1 0 0 1;

1 0 1 0;

1 0 1 1;

1 1 0 0;

1 1 0 1;

1 1 1 0;

1 1 1 1;

];

Divide the input 6 bits into 3 bits. After that, add two three bits. I want to print that value in 4 bits.

There are 64 results.

I'm not good at English, so I'll mark it with numbers.

6bits input64 -> Neural network system -> 4bits output64