필터 지우기
필터 지우기

Tricky formula with cumulative sum

조회 수: 4 (최근 30일)
Peta
Peta 2014년 9월 23일
댓글: Peta 2014년 9월 24일
I’m trying to calculate a ”standard deviation series” with a formula that involves a cumulative sum, but my matlab skills apparently aren’t sufficient to figure out how to type the formula in matlab.
The equation I want to write can be seen in step 5. Here: http://en.wikipedia.org/wiki/Rescaled_range
I have a vector “X” and a vector “u” and if I just use the cumulative sum command matlab doesn’t interpret the sum in the way I want it. This is how I want the calculation to look like:
Y(1) = ( X(1)-u(1) )^2
Y(2) = ( X(1)-u(2) )^2 + ( X(2)-u(2) )^2
Y(3) = ( X(1)-u(3) )^2 + ( X(2)-u(3) )^2+ ( X(3)-u(3) )^2
Y(4) = ( X(1)-u(4) )^2 + ( X(2)-u(4) )^2+ ( X(3)-u(4) )^2+ ( X(4)-u(4) )^2
….and so on
So in other words the calculation is increasing in size for each step and keeps X(1), X(2), X(3) and so on but only uses the most current value for “u” in each of the calculations.
This should be pretty simple right? How do I make it happen in matlab, any ideas?
Thanks
  댓글 수: 3
Star Strider
Star Strider 2014년 9월 23일
It looks like the summation inside the radical in ‘Step 5’.
Peta
Peta 2014년 9월 24일
Yes exactly, I just wrote the (x(i)-u)^2 summation part, then it should be multiplied with 1/t and square rooted. Or do you think I interpreted the formula wrong?

댓글을 달려면 로그인하십시오.

채택된 답변

Roger Stafford
Roger Stafford 2014년 9월 24일
편집: Roger Stafford 2014년 9월 24일
To use 'cumsum' you need to get the u's out of the squared expression. Let's assume X and u are row vectors.
Y = cumsum(X.^2)-2*cumsum(X).*u+(1:size(u,2)).*u.^2;
  댓글 수: 1
Peta
Peta 2014년 9월 24일
Aah, beautiful! That did exactly what I wanted it to! I would never have figured that out myself, thanks!

댓글을 달려면 로그인하십시오.

추가 답변 (1개)

Star Strider
Star Strider 2014년 9월 23일
This seems to do what you want:
X = randi(20,1,10); % Create ‘X’
u = 1:10; % Create ‘u’
for k1 = 1:10
Y(k1) = sum((X(1:k1)-u(k1)).^2);
end
At least it produces the correct result (checked with manual calculation).

카테고리

Help CenterFile Exchange에서 Mathematics에 대해 자세히 알아보기

제품

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by