How could I Transform some lines from Matlab to Python ::

I am trying to transform the following lines into python, I already did however, I got an error not sure if I did it correct or not as I am new to python not sure about some lines: I attached both codes : In matlab (works fine):

  clear all;
    for ii = 1:nu_y
        if (ii == 1)
        t1 = 0; 
        t2 = p(ii);
        Z(1:4) = linspace(t1,t2,4)
        else
        t1 = Z(3*ii-2);
        t2 = t1+p(ii);
        Z(3*ii-2:3*ii+1) = linspace(t1,t2,4)
       end
    end
    
    

In python:

    import numpy as np
    nu_x =     1
    nu_y =     2
    p    =     np.array([0.2,0.2])
    for ii in range (nu_y):
        if (ii == 1):
            t1 = 0
            t2 = p[ii]
            Z[1,3] = np.linspace(t1,t2,3)
        else:
            t1 = Z[2*ii-1]
            t2 = t1+p[ii]
            Z[2*ii-1,2*ii+1] = linspace(t1,t2,3)

Answer 1

[Walter Roberson]

    for ii = 1:nu_y
        if (ii == 1)

That is intended to test for the first ii

   for ii in range (nu_y):
        if (ii == 1): 

In Python, the first ii value is 0

         Z(1:4) = linspace(t1,t2,4)

In MATLAB, that would be the first four entries in Z

       Z[1,3] = np.linspace(t1,t2,3)

You have asked python to create a list with three elements (not 4 like you did in MATLAB), and you have asked Python to assign it to single location in a 2D array. If you were wanting to assign to the first three elements in Z then you should assigning to Z[0:2] .

It is not clear to me why you changed from 4 elements in MATLAB into 3 elements in Python.

[Mark Sc]

@Walter Roberson

Thank you so much for you comment, I got your feedback, and I editied the code as the following:

import numpy as np
nu_x =     1
nu_y =     3
p    =     np.array([0.2,0.2,0.1])
Z=[]
for ii in range(nu_y):
        if (ii == 0):
            t1 = 0
            t2 = p[ii]
            Z[0:3] = np.linspace(t1,t2,4)
        else:
            t1 = Z[3*ii-2]
            t2 = t1+p[ii]
            Z[3*ii-2:3*ii+1] = np.linspace(t1,t2,4)

print(Z)

But still not get the same result as Matlab, have no idea for the reason,

clear all;
 nu_y=3;
 p=[0.2,0.2,0.1]
    for ii = 1:nu_y
        if (ii == 1)
        t1 = 0; 
        t2 = p(ii);
        Z(1:4) = linspace(t1,t2,4)
        else
        t1 = Z(3*ii-2);
        t2 = t1+p(ii);
        Z(3*ii-2:3*ii+1) = linspace(t1,t2,4)
       end
   end

Z

[Walter Roberson]

        Z(3*ii-3:3*ii) = linspace(t1,t2,4)

[Mark Sc]

@Walter Roberson

I got the following error:

IndexError: list index out of range

Also, I tried to change the t1=Z(3*ii-2); to t1=Z[3*ii-1] but still error

[Walter Roberson]

            Z[3*ii-3:3*ii] = np.linspace(t1,t2,4)

[Mark Sc]

@Walter Roberson

Thank you so much for your help, however still unfortunely gives wrog answer, ?

Not as Matlab ??

[Mark Sc]

@Walter Roberson I attached the modified version of the code,

if you are run the same in Matlab give you different answer

import numpy as np
nu_x =     1
nu_y =     4
p    =     np.array([0.2,0.2,0.1,0.4])
Z=[]
for ii in range(nu_y):
        if (ii == 0):
            t1 = 0
            t2 = p[ii]
            Z[0:3] = np.linspace(t1,t2,4)
        else:
            t1 = Z[2*ii-2]
            t2 = t1+p[ii]
            Z[3*ii-3:3*ii] = np.linspace(t1,t2,4)

print(Z)

In matlab:

clear all;
 nu_y=4;
 p=[0.2,0.2,0.1,0.4]
    for ii = 1:nu_y
        if (ii == 1)
        t1 = 0; 
        t2 = p(ii);
        Z(1:4) = linspace(t1,t2,4)
        else
        t1 = Z(3*ii-2);
        t2 = t1+p(ii);
        Z(3*ii-2:3*ii+1) = linspace(t1,t2,4)
       end
   end

Z