Separating the Z Vector of a matrix

조회 수: 3 (최근 30일)
Shane
Shane 2014년 9월 15일
답변: Shane 2014년 9월 30일
Say we have a Data Cube that is 768x320x361(i.e. X, Y, Z coordinates). I generate 2 variable list called VarName1 and VarName2 that hold X and Y coordinates. My goal is to get only the first 124 values of the Z vector at each X and Y point and assign the values to columns. Here is the code I have wrote so far
pixswir=zeros(361,12);
for i = 1:12
%grabs all the pixel values in the z direction
pix = img(VarName2(i),VarName1(i),:);
pixswir(:,i)=pix(:);
end
This will return a matrix 361 x 12 but I only want to grab the first 124 data points of the Z vector and assign them to pixswir so that i have a 124 x 12 matrix. The rest of the values i wish to assign to pixVnir in a 231 x 12 matrix( NOTE:the points on the Z vector 125 to 129 are transition data that is not needed). Any help would be grateful I have tried a few things and keep getting "Subscripted assignment dimension mismatch"

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Shane
Shane 2014년 9월 30일
Because of the disparity in the two sensors I had to read in the two sensors independently. The sensor one is the fist 124 bands and sensor two 231 bands. to do this I created 2 zeros mask that could be use to fill
pixswir=zeros(231,length(listp));
pixVnir=zeros(124,length(listp));
The first vector of wavelength was grabbed using a for loop to match each point to my list of points which I called VarName2 for y and VarName1 for x coordinates.
for i = 1:length(listp)
%grabs all the pixel values in the z direction
pix = img(VarName2(i),VarName1(i),:);
pixVnir(:,i)=pix(1:124);
end
I used a similar posses for the other set but i had to create a new x coordinate based on the offset of the two sensors i.e.
tempVar=zeros(length(listp),1);
for ii = 1:length(listp)
tempVar(ii)=VarName1(ii)+Disoffset(ii);
end
Then it could be pressed the same as the first only with the tail end of the bands "pixswir(:,i)=pix2(131:end);" This allowed me to append the images to for a new 355 by 20 matrix with each column containing the z vector of that pixel

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