what will be the solution for this error
이전 댓글 표시
function idx=nomc(meas)
W=SimilarMatrix(meas,1);
D=diag(sum(W));
L=D-W;
Lsym=(D^(-1/2))*L*(D^(-1/2));
[ev ed]=eig(Lsym);
d=diag(ed); %#ok<NASGU>
V=ev(:,1:3);
for i=1:250
for j=1:7
U(i,j)=V(i,j)/sqrt(sum(V(i,:).^2)); %#ok<AGROW>
end
end
idx=kmeans(U,3);
figure;plot(idx);
result=[length(find(idx==1)),length(find(idx==2)),length(find(idx==3))];
getting error
??? Attempted to access V(1,4); index out of bounds because
size(V)=[143,3].
Error in ==> nomc at 11
U(i,j)=V(i,j)/sqrt(sum(V(i,:).^2)); %#ok<AGROW>
Error in ==> Normalizemeanseg at 120
f=nomc(y);
댓글 수: 2
Rushikesh Tade
2014년 9월 12일
can you provide "meas" variable in mat format or provide dimensions?
Poonam
2014년 9월 12일
답변 (1개)
Titus Edelhofer
2014년 9월 12일
Hi,
you write
V = ev(:, 1:3);
so V has three columns. But your loop on j is
for j=1:7
That doesn't match ...
Titus
댓글 수: 4
Poonam
2014년 9월 12일
Pierre Benoit
2014년 9월 12일
편집: Pierre Benoit
2014년 9월 12일
Well you should check the value of i then. You should use the sizes of V for your loop boundaries rather than some magic numbers.
Type
dbstop if error
in your command window before running your code, it will be easier to understand what went wrong.
Image Analyst
2014년 9월 12일
Poonam, I think you're mistaken. If the error says
Attempted to access V(1,4);
and your code is
for j=1:3
Then there is no way the second index of V could be 4 in this line
U(i,j)=V(i,j).....
Pierre Benoit
2014년 9월 12일
편집: Pierre Benoit
2014년 9월 12일
Well, my guess was that this is no longer j that was causing a problem but i since the boundary of this loop is also quite arbitrary. And, maybe the author forgot to tell us or didn't see that the error changed a little.
But at this point, we can only guess given how little information we have.
카테고리
도움말 센터 및 File Exchange에서 Matrix Indexing에 대해 자세히 알아보기
제품
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!