Most populated range of floating point numbers in array
조회 수: 6 (최근 30일)
이전 댓글 표시
histc can be used on a floating point array to find the bin with the largest number of elements. However these bins are fixed, and for a fixed width of bin, might not be optimal.
Example
a=[0 0.01 0.4 0.45 0.55 0.56 0.60]
histc(a,[0 0.5 1])
ans =
4 3 0
So the most frequent bin is [0, 0.5]. However, I am interested in a function that finds the range of at most 0.5 wide, with the most elements, so in this case [0.4, 0.6] which contains 5 elements. Does anybody know an elegant way of doing this?
댓글 수: 0
채택된 답변
Roger Stafford
2014년 9월 8일
Perhaps you won't consider this for-loop solution elegant, but it should be computationally efficient. I will assume that your array 'a' is already in ascending order, as in your example. If not, you should sort it first before using the following code:
d = 0.5; % <-- or whatever you choose
n = length(a);
i1 = 1;
for i2 = 1:n
if a(i2)-a(i1) <= d
m = i2;
else
i1 = i1+1;
end
end
The interval [a(m-n+i1),a(m)] is of width less than or equal to d and contains the maximum number of points among such intervals. If there are other such intervals with the same number of points, this is the first one encountered.
추가 답변 (1개)
Honglei Chen
2014년 9월 8일
You can just do
histc(a,[0 0.4 0.6 1])
if you know for sure you want the interval [0.4 0.6]. Otherwise, you can use hist
y = hist(a,[0 0.5 1])
which specifies the center
참고 항목
카테고리
Help Center 및 File Exchange에서 Logical에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!