finding the area using Shoelace Polygon formula
조회 수: 24 (최근 30일)
이전 댓글 표시
function area = shoelace (x,y)
n = length(x);
area = 0;
for i = 1 : n-1
area = area + (x(i) + x(i+1)) * (y(i) - y(i+1));
end
area = abs(area)/2;
end
How do I assign the values of x and y and get the answer on the command windows.
댓글 수: 0
답변 (1개)
Aykut Satici
2014년 9월 4일
I don't think that is quite the right formula.
Using the correct formula, your function would be very similar:
function area = shoelace(x,y)
n = length(x);
xp = [x; x(1)];
yp = [y; y(1)];
area = 0;
for i = 1:n
area = area + det([xp(i), xp(i+1); yp(i), yp(i+1)]);
end
area = 1/2*abs(area);
Then you can call this function with two vectors containing the vertices of any n-gon:
x = rand(100,1);
y = rand(100,1);
shoelace(x,y)
You can check the result by comparing it with MATLAB's built-in function "polyarea"
댓글 수: 0
참고 항목
카테고리
Help Center 및 File Exchange에서 Elementary Polygons에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!